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ioda
3 years ago
8

The area of the picture is 100 square inches. The length is 4 times the width. Find the length and width of the picture.

Mathematics
2 answers:
Burka [1]3 years ago
8 0

Answer:

400

Step-by-step explanation:

snow_lady [41]3 years ago
5 0

Answer:

Length: 20 Width: 5

Step-by-step explanation:

I used a calculator ;w;

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Does somebody knows this one?
Katarina [22]

Answer:

ok so first we need to find the area of the circle inside which is a=Pi*raduis^2

a=pi*1(radius is half of diamater)

a=3.14

ok then the area of the sqare including the circle is 16 so

16-3.14=12.86

this is is aprox since the area of pi is infinite and i just used 3.14

Hope This Helps!!!

8 0
2 years ago
Please help me with this math
Montano1993 [528]

Answer:

um I don't understand it pls be more specific and I will help

8 0
2 years ago
7g + 11 subtracted from 12
BlackZzzverrR [31]
A subtracted from b means b-a

7g+11 subtracted from 12 means 12-(7g+11)=12-1(7g+11)=12-7g-11=12-11-7g=1-7g
5 0
2 years ago
adiocarbon dating of blackened grains from the site of ancient Jericho provides a date of 1315 BC ± 13 years for the fall of the
Zigmanuir [339]

Answer:

\left(\frac{m(t)}{m_{o}} \right)_{min} \approx 0.659 and \left(\frac{m(t)}{m_{o}} \right)_{max} \approx 0.661

Step-by-step explanation:

The equation of the isotope decay is:

\frac{m(t)}{m_{o}} = e^{-\frac{t}{\tau} }

14-Carbon has a half-life of 5568 years, the time constant of the isotope is:

\tau = \frac{5568\,years}{\ln 2}

\tau \approx 8032.926\,years

The decay time is:

t = 1315\,years + 2007\,years \pm 13\,years (There is no a year 0 in chronology).

t = 3335 \pm 13\,years

Lastly, the relative amount is estimated by direct substitution:

\frac{m(t)}{m_{o}} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{\mp\frac{13\,years}{8032.926\,years} }

\left(\frac{m(t)}{m_{o}} \right)_{min} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{-\frac{13\,years}{8032.926\,years} }

\left(\frac{m(t)}{m_{o}} \right)_{min} \approx 0.659

\left(\frac{m(t)}{m_{o}} \right)_{max} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{\frac{13\,years}{8032.926\,years} }

\left(\frac{m(t)}{m_{o}} \right)_{max} \approx 0.661

4 0
2 years ago
Find AC and FB.<br> Points B, D, and F are midpoints of the sides of ACE. EC=40 and DF=18.
ANTONII [103]
The second option. A is 36 and B is 20. FD is half of AC, so 18*2 is 36. FB is half of EC, so it’s 20.
4 0
2 years ago
Read 2 more answers
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