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Tju [1.3M]
3 years ago
14

Ten points! Solve for x: 1 < x + 3 < 4

Mathematics
1 answer:
torisob [31]3 years ago
8 0

Answer:

-2 < x < 1

Hope this helps :)

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I NEED HELP ON THIS CONSTRUCTED RESPONSE! :(
Vikentia [17]

Answer:

<em>x < 2</em>

Step-by-step explanation:

-12x - 0.4 > 0.2(36.5x + 80) - 55

-12x - 0.4 > 7.3x + 16 - 55

-19.3x > -38.6

x < 2

4 0
3 years ago
Wah wah wah wah wah? (what is the GCF of 100 and 200?)
Vedmedyk [2.9K]

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100 :)

Step-by-step explanation:

3 0
3 years ago
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Find the solution of the differential equation that satisfies the given initial condition.
Ann [662]

Answer:

I don’t know

Step-by-step explanation:

5 0
3 years ago
In this triangle, which of the following is true?​
Svetradugi [14.3K]

We know that this is a right triangle, so one of the sides has to be 90 (indicated by the square on the corner)  The angles of all triangles must add to exactly 180.  Subtract 90 and 35 from 180

If we do that, we get 55.  We know that the unknown angle is 55 now.  Now, it asks us for b.  We can pythagoras theorem which states that (a^2 + b^2 = c^2)  We already know c (c is 20)  It does not tell us 2 of the sides but we do know that the answer is either B or D.  

The side opposite of 90* should be the largest.  The size opposite of 55 would be the second largest one.  The side opposite of 35 would be the smallest one.  Using pythagoras theorem again, I can try plugging in both 11.47 and 16.38 with c^2 - b^2 = a^2  

11.47:

400 - 132 =268  (sq root now = 16.37) this would mean that A is larger than B.  B should be larger than A.  Try the other one

16.37:

400 -268 = 132 (sq root = 16.37) this would mean that B is larger than A which is what we want.

Thus, 16.37  = B and the last option would be correct (D)

Hope this helps, give an honest rating for me please

7 0
3 years ago
Divya wants to find x in the figure. What theorem can Divya use to solve for x ? Alternate Exterior Angles Theorem Alternate Ext
IceJOKER [234]

Answer:

Proof of alternate exterior angles theorem. Consider the diagram above. The two lines are parallel.

Step-by-step  i took the test but i guess i will show u % of the x and y quardernates and then x5 andd 6

8 0
3 years ago
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