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Sergio039 [100]
3 years ago
12

calculate the total potential energy in kj of an object whose mass is 20 kg when it is located 20 m below a datum level in a loc

ation where g=9.5 m/s^2
Mathematics
1 answer:
Airida [17]3 years ago
5 0

Answer:

The energy in object is 3.8 Kilo Joules.  

Step-by-step explanation:

We are given the following in the question:

Mass = 20 kg

Height,h = 20 m

g=9.5 m/s^2

Formula:

Potential energy  =

E = Mgh

Putting value we get,

E = 20(20)(9.5)\\E = 3800~J\\E = 3.8~KJ

Thus, the energy in object is 3.8 Kilo Joules.

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AnnZ [28]

Answer:

35

Step-by-step explanation:

4/14 divided by 2/2 is 2/7 and then 2/7 times 5/5 is 10/35 so its 35

4 0
2 years ago
PLEASE ANSWER FAST
Dmitrij [34]
Hello there!

The answer to this question will be answer choice A.

When using the SAS postulate, we need two pairs of sides and the pair of the angles between those two sides to be congruent.

It is given that one pair of sides are congruent, along with a pair of congruent angles.

We want the congruent angle to be between two congruent sides, thus AC must be congruent to EC in order for these triangles to be proven congruent by the SAS postulate.

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6 0
2 years ago
Select all irrational numbers. √4 √8 √10 √15 √35
larisa [96]
√4 =2
√8= 2<span>√<span>2
</span></span>√10=√10 as (Decimal: 3.162278)
√15=√15 as (Decimal: 3.872983)
√35=√35 as (Decimal: 5.91608)
6 0
3 years ago
The port of South Louisiana, located along 54 miles of the Mississippi River between New Orleans and Baton Rouge, is the largest
Ksenya-84 [330]

Answer:

a) 0.7287

b) 0.9663

c) 0.237

d) 3.65 tons of cargo per week or more that will require the port to extend its operating hours.  

Step-by-step explanation:

We are given the following information in the question:

Mean, μ =  4.5 million tons of cargo per week

Standard Deviation, σ = 0 .82 million tons

We are given that the distribution of number of tons of cargo handled per week is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) P( port handles less than 5 million tons of cargo per week)

P(x < 5)

P( x < 5) = P( z < \displaystyle\frac{5 - 4.5}{0.82}) = P(z < 0.609)

Calculation the value from standard normal z table, we have,  

P(x < 5) =0.7287= 72.87\%

b) P( port handles 3 or more million tons of cargo per week)

P(x \geq 3) = P(z \geq \displaystyle\frac{3-4.5}{0.82}) = P(z \geq −1.82926)\\\\P( z \geq −1.82926) = 1 - P(z < -1.829)

Calculating the value from the standard normal table we have,

1 - 0.0337 = 0.9663 = 96.63\%\\P( x \geq 3) = 96.63\%

c)P( port handles between 3 million and 4 million tons of cargo per week)

P(3 \leq x \leq 4) = P(\displaystyle\frac{3 - 4.5}{0.82} \leq z \leq \displaystyle\frac{4-4.5}{0.82}) = P(-1.829 \leq z \leq -0.609)\\\\= P(z \leq -0.609) - P(z < -1.829)\\= 0.271-0.034 = 0.237= 23.7\%

P(3 \leq x \leq 4) = 23.7\%

d) P(X=x) = 0.85

We have to find the value of x such that the probability is 0.85.

P(X > x)  

P( X > x) = P( z > \displaystyle\frac{x - 4.5}{0.82})=0.85  

= 1 -P( z \leq \displaystyle\frac{x - 4.5}{0.82})=0.85  

=P( z \leq \displaystyle\frac{x - 4.5}{0.82})=0.15  

Calculation the value from standard normal z table, we have,  

P( z \leq -1.036) = 0.15

\displaystyle\frac{x - 4.5}{0.82} = -1.036\\x = 3.65

Thus, 3.65 tons of cargo per week or more that will require the port to extend its operating hours.

8 0
2 years ago
Need answer ASAP thanks
olga55 [171]

Answer:

0.05

Step-by-step explanation:

hope this helps! :D

you have a miraculous everybody!! <3

6 0
2 years ago
Read 2 more answers
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