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Sergio039 [100]
3 years ago
12

calculate the total potential energy in kj of an object whose mass is 20 kg when it is located 20 m below a datum level in a loc

ation where g=9.5 m/s^2
Mathematics
1 answer:
Airida [17]3 years ago
5 0

Answer:

The energy in object is 3.8 Kilo Joules.  

Step-by-step explanation:

We are given the following in the question:

Mass = 20 kg

Height,h = 20 m

g=9.5 m/s^2

Formula:

Potential energy  =

E = Mgh

Putting value we get,

E = 20(20)(9.5)\\E = 3800~J\\E = 3.8~KJ

Thus, the energy in object is 3.8 Kilo Joules.

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84. Use properties of exponents to rewrite each expression with only positive, rational exponents. Then find the numerical value
Yakvenalex [24]

Answer:

a) 1/27

b) 16

c) 1/8

Step-by-step explanation:

a) x^{-3/2}

One of the properties of the exponents tells us that when we have a negative exponent we can express it in terms of its positive exponent by turning it into the denominator (and changing its sign), so we would have:

x^{-3/2}=\frac{1}{x^{3/2} }

And now, solving for x = 9 we have:

\frac{1}{x^{3/2}}=\frac{1}{9^{3/2} }  =\frac{1}{27}

b) y^{4/3}

This is already a positive rational exponent so we are just going to substitute the value of y = 8 into the expression

y^{4/3}=8^{4/3}=16

c) z^{-3/4}

Using the same property we used in a) we have:

z^{-3/4}=\frac{1}{z^{3/4} }

And now, solving for z = 16 we have:

\frac{1}{z^3/4} } =\frac{1}{16^{3/4} } =\frac{1}{8}

4 0
3 years ago
ASAP please help me I need this quick <br> The question and answers are in the picture
Ilia_Sergeevich [38]

Answer:

25

Step-by-step explanation:

maybe this will help you

4 0
3 years ago
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jonny [76]

4 < 4(6y - 12) - 2y       |use distributive property

4 < (4)(6y) + (4)(-12) - 2y

4 < 24y - 48 - 2y       |add 48 to both sides

52 < 26y      |divide both sides by 26

2 < y → y > 2

---------------------------------------------------------

4x + 3 < 3x + 6      |subtract 3 from both sides

4x < 3x + 3       |subtract 3x from both sides

x < 3

------------------------------------------------------------

-5r + 6 ≤ -5(r + 2)        |use distributive property

-5r + 6 ≤ (-5)(r) + (-5)(2)

-5r + 6 ≤ -5r - 10         |add 5r to both sides

6 ≤ -10     FALSE

No solution

-------------------------------------------------------------

-2(6 + s) ≥ -15 - 2s        |use distributive property

(-2)(6) + (-2)(s) ≥ -15 - 2s

-12 - 2s ≥ -15 - 2s        |add 2s to both sides

-12 ≥ -15     TRUE

All real numbers

-------------------------------------------------------------

3s + 6 ≤ -5(s + 2)        |use distributive property

3s + 6 ≤ (-5)(s) + (-5)(2)

3s + 6 ≤ -5s - 10         |subtract 6 from both sides

3s ≤ -5s - 16        |add 5s to both sides

8s ≤ -16         |divide both sides by 8

s ≤ -2

--------------------------------------------------------------

4/3 s - 3 ?

4 0
3 years ago
Quadrilateral ABCD is a parallelogram with diagonals that intersect at point E. If AD=4w-5 DE=4 BE=x/2 BC=7w-17 solve for w.
Alex777 [14]

Answer:

B. w = 4

Step-by-step explanation:

As we know, in a parallelogram length of opposite sides are equal.

so, AD = BC

⇒ 4w - 5 = 7w - 17

⇒ 12 = 3w

⇒ w = 4

8 0
3 years ago
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