Differentiating an integral removes the integral.
f(x) = integral of dt/sqrt(t^3 + 2)
f'(x) = 1/sqrt(x^3 + 2)
f'(1) = 1/sqrt(1^3 + 2)
f'(1) = 1/sqrt(3) = sqrt(3)/3.
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(1/36) = 0.0277777777778
(1/108)^3 = 7.9383224102<span> x 10^-7 </span>
(1/9)^4 = 0.000152415790276
(1/6)^2 = 0.0277777777778
(1/2)^5 = <span>0.03125
The only one that matches with the value of 1/36 is (1/6)^2. Therefore, your answer is C. (1/6)^2
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Answer:
Can you retake the picture please, of the entire Problem?
Step-by-step explanation:

A=future amount
P=present amount
r=rate in decimal
n=number of times per year compounded
t=time in years
given
P=455
r=4%=0.04
n=1
t=2



A=492.128
round
$492.13
3rd option
Answer:36 square inches
Step-by-step explanation: