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inn [45]
3 years ago
15

A zoo charges admission of $4.75 for adults and $2.75 for children. A group of 12 people paid for admission with a 50-dollar bil

l. If the group received at least $9.00 in change, what is the maximum number of adults in the group?

Mathematics
1 answer:
Whitepunk [10]3 years ago
7 0
The maximum number of adults is 4
Read my attachment

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0 A pigeon can fly at a speed of 84 kilometers per hour. How long does it take the pigeon to fly 7 kilometers
QveST [7]
The miles per hour is 84 kilometers per 60 minutes (7:5 ratio) so if we take seven kilometers times the ratio 5/7 we get 5 minutes
7 0
3 years ago
A number equivalent to 63.24
tankabanditka [31]
63.24 is equivalent to 63.240.
7 0
4 years ago
Read 2 more answers
PLS HELP ME
MrRa [10]


false... even if you got 100 on the next test, you would only have an 84 average


Hope this helped!!! :) (comment if you don't understand)

3 0
3 years ago
Kara has four boy cousins and three girl cousins. Write a fraction to represent the part of her cousins that are girls.
earnstyle [38]

Answer:

it would be 3/7

Step-by-step explanation:

3+4=7 3 cousins out of the seven are girls

6 0
4 years ago
A journal article reports that a sample of size 5 was used as a basis for calculating a 95% CI for the true average natural freq
oksano4ka [1.4K]

Answer:

Lower = 231.134- 3.098=228.036

Upper = 231.134+ 3.098=234.232

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n=5 represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

And for this case we know that the 95% confidence interval is given by:

\bar X=\frac{233.002 +229.266}{2}= 231.134

And the margin of error is given by:

ME = \frac{233.002 -229.266}{2}= 1.868

And the margin of error is given by:

ME= t_{\alpha/2} \frac{s}{\sqrt{n}}

The degrees of freedom are given by:

df = n-1 = 5-1=4

And the critical value for 95% of confidence is t_{\alpha/2}= 2.776

So then we can find the deviation like this:

s = \frac{ME \sqrt{n}}{t_{\alpha/2}}

s = \frac{1.868* \sqrt{5}}{2.776}= 1.506

And for the 99% confidence the critical value is: t_{\alpha/2}= 4.604

And the margin of error would be:

ME = 4.604 *\frac{1.506}{\sqrt{5}}= 3.098

And the interval is given by:

Lower = 231.134- 3.098=228.036

Upper = 231.134+ 3.098=234.232

6 0
3 years ago
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