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Nataly_w [17]
3 years ago
6

Simplify to create an equivalent expression.10+46-89 – 4)​

Mathematics
1 answer:
Bogdan [553]3 years ago
3 0

Answer:

c -32q -6

Step-by-step explanation:

10 + 4(-8q-4)

Distribute the 4

10 -32q -16

Combine like terms

-32q +10-16

-32q -6

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Ken paid $12 for two magazines. The cost of each magazine was multiple of $3. What are the possible prices of the magazines?
icang [17]

The price for one magazine is $6. Hope this helps. Happy Thanksgiving

7 0
3 years ago
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Work out area of this semi circle with diameter 10
ANTONII [103]

Area of a circle is pi x r^2

R is the radius which is have the diameter: r = 10/2 = 5

Area of the full circle would be 3.14 x 5^2 = 3.14 x 25 = 78.5 square units.

A semi circle is half a full circle

Area of the semi circle = 78.5/2 = 39.25 square units.

8 0
3 years ago
TO TRANSMIT INFORMATION ON THE INTERNET, LARGE FILES ARE BROKEN INTO PACKETS OF SMALLER SIZES. EACH PACKET HAS 1,500 BYTES OF IN
borishaifa [10]

Answer:

<u>A. It would be needed 20 packets to transmit 30,000 bytes of information.</u>

<u>B. 45'000,000 (45 million) of bytes could be transmitted in 30,000 packets.</u>

Step-by-step explanation:

1. Let's review the data given to us for solving the question:

Size of each packet of information = 1,500 bytes

Number of packets = P

Number of bytes of information = B

2. Let's answer the questions:

A. How many packets would be needed to transmit 30,000 bytes of information?

P = 30,000 ÷ 1,500

P = 20

<u>It would be needed 20 packets to transmit 30,000 bytes of information</u>

<u>B. </u>How much information could be transmitted in 30,000 packets?

B = 30,000 * 1,500

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<u>45'000,000 (45 million) of bytes could be transmitted in 30,000 packets.</u>

6 0
3 years ago
Can someone solve this for me?
Helga [31]

well, we know it's a rectangle, so that means the sides JK = IL and JI = KL, so

\stackrel{JK}{3x+21}~~ = ~~\stackrel{IL}{6y}\implies 3(x+7)=6y\implies x+7=\cfrac{6y}{3} \\\\\\ x+7=2y\implies \boxed{x=2y-7} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{JI}{6y-6}~~ = ~~\stackrel{KL}{2x+20}\implies 6(y-1)=2(x+10)\implies \cfrac{6(y-1)}{2}=x+10 \\\\\\ 3(y-1)=x+10\implies 3y-3=x+10\implies \stackrel{\textit{substituting from the 1st equation}}{3y-3=(2y-7)+10} \\\\\\ 3y-3=2y+3\implies y-3=3\implies \blacksquare~~ y=6 ~~\blacksquare ~\hfill \blacksquare~~ \stackrel{2(6)~~ - ~~7}{x=5} ~~\blacksquare

5 0
1 year ago
Can someone please help
TEA [102]

Answer:

All real numbers

Step-by-step explanation:

The domain represents the x-coordinates, so you can see on the graph that it goes all the way out to both the left and right directions, meaning it covers all the negative numbers, and all the positive numbers. The question is trying to trick you into thinking about the range, but forget about the y-axis for this one.

6 0
3 years ago
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