Answer:
-35
___
27
Step-by-step explanation:
Start by setting up your pairs (x,y)
-5 & 7 are x
3 & 9 are y
X * X
---------- ÷
Y * Y
(-5, 7)
---------
(3, 9)
-35
-------
27
The weight of the air in the room is 172.8 lb if the dimensions of a living room are 18 ft. by 15 ft. by 8ft.
<h3>What is a rectangular prism?</h3>
It is defined as the six-faced shape, a type of hexahedron in geometry.
It is a three-dimensional shape. It is also called a cuboid.
It is given that:
The dimensions of a living room are 18 ft. by 15 ft. by 8ft.
The volume of the living room = volume of the cuboid:
V = length×width×height
V = 18×15×8
V = 2160 cubic ft
The weight of the air = 0.08 lb. per cubic foot
The weight of the air in the room = 0.08×2160
The weight of the air in the room = 172.8 lb
Thus, the weight of the air in the room is 172.8 lb if the dimensions of a living room are 18 ft. by 15 ft. by 8ft.
Learn more about the rectangular prism here:
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There rate is 1.67 or 1.66 repeated a day
The expected length of code for one encoded symbol is

where
is the probability of picking the letter
, and
is the length of code needed to encode
.
is given to us, and we have

so that we expect a contribution of

bits to the code per encoded letter. For a string of length
, we would then expect
.
By definition of variance, we have
![\mathrm{Var}[L]=E\left[(L-E[L])^2\right]=E[L^2]-E[L]^2](https://tex.z-dn.net/?f=%5Cmathrm%7BVar%7D%5BL%5D%3DE%5Cleft%5B%28L-E%5BL%5D%29%5E2%5Cright%5D%3DE%5BL%5E2%5D-E%5BL%5D%5E2)
For a string consisting of one letter, we have

so that the variance for the length such a string is

"squared" bits per encoded letter. For a string of length
, we would get
.
Answer:
Step-by-step explanation:
1) A perfect square is a whole number which is a product of a smaller whole number and itself. Examples of perfect squares are
4(2 × 2)
9(3 × 3)
16(4 × 4)
25(5 × 5)
36(6 × 6)
2) Square root of 4x² is 2x(product of square root of 4 and square root of x²)
3) square of 25 is 5
4) 4x² + 20x + 25
The general formula for solving quadratic equations is expressed as
x = [- b ± √(b² - 4ac)]/2a
From the equation given,
a = 4
b = 20
c = 25
Therefore,
x = [- 20 ± √(20² - 4 × 4 × 25)]/2 × 4
x = [- 20 ± √(400 - 400)]/8
x = [- 20 ± 0]/8
x = - 20/8
x = - 2.5