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3 years ago

14

Jim gets a $20 allowance

2 answers:

natita [175]3 years ago

8 0

He mowed 13 lawns hop i help if so can you make me the braliy

Juliette [100K]3 years ago

5 0

He mows 13 lawns I hope this helps you

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Please Help I will Give Brainest and 100 points and no fake answers

Lady bird [3.3K]

Step-by-step explanation:

$\sqrt{3} is \: between1.7and1.8$

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3 years ago

A coordinate plane graph is shown. Point C is at negative 4 comma 3. Point D is at 1 comma 0. A segment connects the two points.

lina2011 [118]

The distance between them is 5.83 units. Enjoy!

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3 years ago

Read 2 more answers

How do I solve this?

Olin [163]

Well if it is 1 inch per 100 feet, then we already know that 600 feet is 6 inches on the map. Now the 4 is where it gets trickier. Since it's dividing it by 100 each time, you take 4 and divide it by 100 which is 0.04. Therefore, your answer is 6.04 inches on the map.

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3 years ago

For every integer k from 1 to 10, inclusive the "k"th term of a certain sequence is given by (−1)(k+1)∗(12k). If T is the sum of

Katena32 [7]

Answer:

Option D. is the correct option.

Step-by-step explanation:

In this question expression that represents the kth term of a certain sequence is not written properly.

The expression is $(-1)^{k+1}(\frac{1}{2^{k}})$ .

We have to find the sum of first 10 terms of the infinite sequence represented by the expression given as $(-1)^{k+1}(\frac{1}{2^{k}})$ .

where k is from 1 to 10.

By the given expression sequence will be $\frac{1}{2},\frac{(-1)}{4},\frac{1}{8}.......$

In this sequence first term "a" = $\frac{1}{2}$

and common ratio in each successive term to the previous term is 'r' = $\frac{\frac{(-1)}{4}}{\frac{1}{2} }$

r = $-\frac{1}{2}$

Since the sequence is infinite and the formula to calculate the sum is represented by

$S=\frac{a}{1-r}$ [Here r is less than 1]

$S=\frac{\frac{1}{2} }{1+\frac{1}{2}}$

$S=\frac{\frac{1}{2}}{\frac{3}{2} }$

S = $\frac{1}{3}$

Now we are sure that the sum of infinite terms is $\frac{1}{3}$ .

Therefore, sum of 10 terms will not exceed $\frac{1}{3}$

Now sum of first two terms = $\frac{1}{2}-\frac{1}{4}=\frac{1}{4}$

Now we are sure that sum of first 10 terms lie between $\frac{1}{4}$ and $\frac{1}{3}$

Since $\frac{1}{2}>\frac{1}{3}$

Therefore, Sum of first 10 terms will lie between $\frac{1}{4}$ and $\frac{1}{2}$ .

Option D will be the answer.

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3 years ago

Determine the solutions to the quadratic function

Charra [1.4K]

Answer:

B.

Step-by-step explanation:

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3 years ago