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HACTEHA [7]
3 years ago
7

I need help quickly with these problems please see the images thank you so much

Mathematics
1 answer:
mr Goodwill [35]3 years ago
7 0
Using cosine law:
 24 ^ 2 = 10 ^ 2 + 16 ^ 2 -2 * 10 * 16 * cos (G)
 Clearing we have:
 cos (G) = (24 ^ 2-10 ^ 2-16 ^ 2) / (- 2 * 10 * 16)
 cos (G) = - 0.6875
 Clearing the angle:
 G = acos (-0.6875)
 G = 133.4325366
 Rounding:
 G = 133.4
 Answer:
 
G = 133.4
 
option 4
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Hoochie [10]

Answer:

D. 52

Step-by-step explanation:

Add 85 and 45 to get 130.

6.2n-3.7n=130

Subtract 3.7 from 6.2

2.5n=130

divide 130 by 2.5 to find n

N=52

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3 years ago
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What is the equation of the line passing through the points (-3,7) and (3,3)
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\text{Given that,}\\\\(x_1,y_1) = (-3,7)~~ \text{and}~~(x_2,y_2) =(3,3)\\\\\\\text{Slope, }~~ m =\dfrac{y_2-y_1}{x_2 - x_1}= \dfrac{3-7}{3-(-3)} = -\dfrac{4}{3+3}  = -\dfrac 46 = -\dfrac 23\\\\\\\text{Equation with given points ,}\\\\y- y_1 = m(x-x_1)\\\\\implies y -7 = -\dfrac 23 (x +3)\\\\\implies  y -7= -\dfrac 23 x - 2\\\\\implies y = -\dfrac 23 x -2 +7 \\\\\implies y = -\dfrac 23 x +5\\\\\implies 3y = -2x +15 \\\\\implies 2x +3y = 15

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2 years ago
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Rule start at 6 2/3 subtract 1 1/4 show work
KonstantinChe [14]
The answer is 5 5/12.


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3 years ago
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What is the answer of 3125 ÷ 25 and show how you got the answer
yuradex [85]

Answer:

125

Step-by-step explanation:

because 3125 divided 25 equals 125.

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3 years ago
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What do you know about a quadratic equation that has the following points (2, 0) and (10, 0)?
Agata [3.3K]

Answer:

C.  The x-coordinate of the vertex must be 6

Step-by-step explanation:

The parabola intercepts the x-axis when y = 0.

Therefore, if the quadratic equation has the points (2, 0) and (10, 0) then the x-intercepts or "zeros" are x = 2 and x = 10.

The x-coordinate of the vertex is the midpoint of the zeros.

\sf \implies midpoint=\dfrac{2+10}{2}=6

Therefore, the solution is option C.

<u>Additional Information</u>

The leading coefficient of a quadratic tells us if the parabola opens upwards or downwards:

  • Positive leading coefficient = parabola opens upwards
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We have not been given this information and so therefore cannot determine the way in which it opens.

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We have not been given the full quadratic equation, and so we cannot determine if the parabola is wider (or narrower) than the parent function.

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