All categories

1 year ago

What is the approximate length in inches of the radius of the circle

Mathematics

1 answer:

Mice21 [21]1 year ago

6 0

Given

The area of the circle is 1200 square inches.

To find the radius of the circle.

Explanation:

It is given that,

The area of the circle is 1200 square inches.

That implies,

$\begin{gathered} Area\text{ }of\text{ }the\text{ }circle=\pi r^2 \\ \pi r^2=1200 \\ r^2=\frac{1200}{\pi} \\ r^2=381.972 \\ r=\sqrt{381.972} \\ r=19.5 \\ r=20inches \end{gathered}$

Hence, the radius of the circle is 20 inches.

You might be interested in

Dilate the trapezoid using center (-3,4) and scale factor 1/2.

pochemuha

The coordinates of the vertices of the image of the trapezoid are given as;

A'(x, y) = (- 4, 1), B'(x, y) = (- 2, 1), C'(x, y) = (- 5 / 2, 5 / 2) , D'(x, y) = (- 7 / 2, 5 / 2).

<h3>How to find the image of a trapezoid by dilation?</h3>

In this question we have a representation of a trapezoid, whose image has to be generated by a kind of rigid transformation known as dilation, whose equation is described :

P'(x, y) = O(x, y) + k · [P(x, y) - O(x, y)]

Where O(x, y) - Center of dilation

k - Scale factor

And P(x, y) - Coordinates of the original point, P'(x, y) - Coordinates of the resulting point.

Since k = 1 / 2, A(x, y) = (- 5, - 2), B(x, y) = (- 1, - 2), C(x, y) = (- 2, 1), D(x, y) = (- 4, 1), O(x, y) = (- 3, 4),

Therefore, the coordinates of the vertices of the image are:

Point A'

A'(x, y) = O(x, y) + k · [A(x, y) - O(x, y)]

A'(x, y) = (- 3, 4) + (1 / 2) [(- 5, - 2) - (- 3, 4)]

A'(x, y) = (- 3, 4) + (1 / 2) (- 2, - 6)

A'(x, y) = (- 3, 4) + (- 1, - 3)

A'(x, y) = (- 4, 1)

Point B';

B'(x, y) = O(x, y) + k [B(x, y) - O(x, y)]

B'(x, y) = (- 3, 4) + (1 / 2) [(- 1, - 2) - (- 3, 4)]

B'(x, y) = (- 3, 4) + (1 / 2) (2, - 6)

B'(x, y) = (- 3, 4) + (1, - 3)

B'(x, y) = (- 2, 1)

Point C';

C'(x, y) = O(x, y) + k · [C(x, y) - O(x, y)]

C'(x, y) = (- 3, 4) + (1 / 2) [(- 2, 1) - (- 3, 4)]

C'(x, y) = (- 3, 4) + (1 / 2) (1, - 3)

C'(x, y) = (- 3, 4) + (1 / 2, - 3 / 2)

C'(x, y) = (- 5 / 2, 5 / 2)

Point D'

D'(x, y) = O(x, y) + k [D(x, y) - O(x, y)]

D'(x, y) = (- 3, 4) + (1 / 2) [(- 4, 1) - (- 3, 4)]

D'(x, y) = (- 3, 4) + (1 / 2) (- 1, - 3)

D'(x, y) = (- 3, 4) + (- 1 / 2, - 3 / 2)

D'(x, y) = (- 7 / 2, 5 / 2)

To learn more on dilations:

brainly.com/question/13176891

#SPJ1

3 0

1 year ago

12 divided by 1/4 please help got a test next Monday

Gala2k [10]

Answer:

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

The path of a ball thrown can be modeled by the equation f(x)=−16x^2+45x+6, where x is the horizontal distance. Use a transforma

andrey2020 [161]

Answer:

g(x) = -4x^2 +(45/2)x +6

Step-by-step explanation:

A function is scaled horizontally by replacing x with x/k, where k is the expansion factor. Here, we want to expand the graph horizontally by a factor of 2, so the new function will be f(x/2).

g(x) = f(x/2) = -16(x/2)^2 +45(x/2) +6

g(x) = -4x^2 +(45/2)x +6

8 0

2 years ago

Flying against the jetstream, a jet travels 7380 miles in 9 hours. Flying with the jetstream, the same jet travels 9920 miles in

Damm [24]

Answer:

The rate of the jet in still air = 1030 miles per hour

And 210 miles per hour is the rate of the stream.

Step-by-step explanation:

Let the speed of the jet in still air be $x$ miles per hour.

And,the speed of the jetstream be $y$ miles per hour.

Key:So when it is moving against the stream speed will be $(x-y)$ and when it is moving with the stream, speed will be $(x+y)$

And we know that.

Distance=Speed multiplied with time.

Arranging the equation.

$9920=8 \times (x+y)$ ...equation 1

$7380=9 \times (x-y)$ ...equation 2

Working with the equation by using elimination method.

Dividing equation 1 with 8 and equation 2 with 9.We will have

1240= $(x+y)$ ...eqn 3

820= $(x-y)$ ...eqn 4

Now adding both the equation will decimate y.

1240+820=2 $x$

2060=2 $x$

Dividing with 2 both sides.

1030= $x$

By plugging the value of $x$ we can find y in equation 3.

1240=1030 + $y$

Subtracting 1030 from both sides.

1240-1030= $y$

$y$ =210 miles per hour

So the rate of the jet in still air = 1030 miles per hour

And 210 miles per hour is the rate of the jet stream.

6 0

3 years ago

If anyone knows how to do science

Luda [366]

Answer:

im using my own knowledge hopefully this is helpful

Orion

milky way

life

earth

years

G2V (I'm not sure with this one)

earths

Step-by-step explanation:

5 0

3 years ago