Answer:
Quadrilateral ABCD is not a square. The product of slopes of its diagonals is not -1.
Step-by-step explanation:
Point A is (-4,6)
Point B is (-12,-12)
Point C is (6,-18)
Point D is (13,-1)
Given that the diagonals of a square are perpendicular to each other;
We know that the product of slopes of two perpendicular lines is -1.
So, slope(m) of AC × slope(m) of BD should be equal to -1.
Slope of AC = (Change in y-axis) ÷ (Change in x-axis) = (-18 - 6) ÷ (6 - -4) = -24/10 = -2.4
Slope of BD = (Change in y-axis) ÷ (Change in x-axis) = (-1 - -12) ÷ (13 - -12) = 11/25 = 0.44
The product of slope of AC and slope of BD = -2.4 × 0.44 = -1.056
Since the product of slope of AC and slope of BD is not -1 hence AC is not perpendicular to BD thus quadrilateral ABCD is not a square.
The probability of drawing exactly one red ball is given by:

the probability of drawing two red balls is given by:

The probability of drawing at least one red ball is:
P(1 red ball) + P(2 red balls) = 16/28 + 6/28 = 11/14.
The answer is
1/2x-7=1/3x-4,
1/2x-3=1/3x,
1/2x-1/3x=3
1/6x=3/1/6
Final answer x=18
I hope you understand and best wishes!!
To solve the set of equations given above, we can use the substitution method where we substitute one equation to the other and solving for one variable. We do as follows:
<span>0.4x - 0.1y = 2
x = 5 + 0.25y
0.2x + 0.5y = 1
</span>0.2(5 + 0.25y)+ 0.5y = 1
y = 0
x = 5
Therefore, the correct answer from the choices is option A, (5,0).
5 times
5*10^5= 500,000
1*10^5= 100,000