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3 years ago

Helppp Plsss Asap!!! Thanks

Mathematics

1 answer:

tester [92]3 years ago

4 0

Answer:

Step-by-step explanation:

The average rate of change is

f(x2) - f(x1)

-----------------

x2-x1

We want to find the change from 1 to 3

f(3) = 8

f(1) = 2

f(3) - f(1) 8-2 6

----------------- = ------------ = ---- = 3

3-1 2 2

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How to solve? im doing piecewise functions

Novosadov [1.4K]

$g(x) = \begin{cases} -x + 4 & \text{if } x \le -1 \\ 3 & \text{if } -1$

then by this definition,

g(0) = 3 … … … (since -1 < 0 < 2)

and

g(1) = 3 … … … (also because -1 < 1 < 2)

7 0

3 years ago

Gabriela has an apartment that costs 30% of her monthly budget, which is $3,575. How much is her rent?

enot [183]

Answer:

Her rent is $1072.5

Step-by-step explanation:

Monthly budget: $3,575

Her rent is 30% of her monthly budget. Since 30% = 0.3, we can multiply our monthly budget with 0.3 to get 30% of it.

30% * 3575 = 0.3 * 3575 = 1072.5

Answer: $1072.5

5 0

3 years ago

Find the counterclockwise circulation and outward flux of the field Fequals7 xy Bold i plus 2 y squared Bold j around and over t

77julia77 [94]

Answer:

The counterclockwise circulation is $\frac{7}{12}$ and the outward flux is $\frac{11}{15}$

Step-by-step explanation:

We are given the field $F(x,y) = (7xy,2y^2)$ . A picture of the region and the path we are considering is attached. Recalll the following theorems.

Given a field of the form F(x,y)=(f(x,y),g(x,y) with f,g having continous partial derivates, C is a closed path counterclockwise oriented, R is the region enclosed by C and n is the normal vector pointing outwards of the path C. Then

$\oint_C F\cdot dr =\iint_R \frac{\partial f}{dy}- \frac{\partial g}{dx} dA$ (this one calculates the counterclockwise circulation)

$\oint_C F\cdot n ds =\iint_R (\frac{\partial f}{dx}+ \frac{\partial g}{dy} dA$ (This one calculates the outward flux)

Then, recall that in our case f(x,y) = 7xy, g(x,y)=2y^2[/tex]. Then

$\frac{\partial f}{dx} = 7y,\frac{\partial f}{dy} = 7x$

$\frac{\partial g}{dx}=0, \frac{\partial g}{dy} = 4y$ .

Note that we just need to describe our region R. The region R lies between the parabola y=x^2 and the line y=x. Thus, one way to describe the region is as follows $0\leq x \leq 1, x^2\leq y \leq x$ . Then, using the previous results, we get that

$\oint_C F\cdot dr =\int_{0}^{1}\int_{x^2}^{x}7x-0dydx = 7\int_{0}^1x(x-x^2)dx = 7 \left.(\frac{x^3}{3}-\frac{x^4}{4})\right|_{0}^1 = 7(\frac{1}{3}-\frac{1}{4}) = \frac{7}{12}$ (circulation)

$\oint_C F\cdot n ds=\int_{0}^{1}\int_{x^2}^{x}7y+4ydydx = \frac{11}{2}\int_{0}^1\left.y^2\right_{x^2}^{x}dx = \frac{11}{2}\int_{0}^{1}x^2-x^4 dx = \frac{11}{2}\left(\frac{x^3}{3}-\frac{x^5}{5})\right|_{0}^{1}=\frac{11}{2}(\frac{1}{3}-\frac{1}{5})=\frac{11}{15}$ (flux)

5 0

3 years ago

What is the area of the rectangle? A.11 square centimeters

Vikki [24]

Answer:

Step-by-step explanation:

Area of a rectangle = width times length therefore the equation is 7 times 4 = 28.

8 0

3 years ago

The cost of a jacket increased from $65.00 to 76.70. what is the percentage increase of the jacket?

VladimirAG [237]

Answer:

15.2542372881 %

Step-by-step explanation:

65/76.70=

0.84745762711 *100=

84.7457627119

100- 84.7457627119= 15.2542372881

Sorry i like all my numbers

4 0

4 years ago

Helppp Plsss Asap!!! Thanks​

Helppp Plsss Asap!!! Thanks