Total number of marbles=5+3+4=12
Probability of picking a red marble =5/12
Answer:
B. 10
Step-by-step explanation:
First, we need to recognize that the two triangles are similar (the triangle with a leg value of 21 and the triangle with a leg value of 4 and hypotenuse x)
Let's first label the leg of the second triangle as y.
Then, we can set up this equation
Cross multiplying gives us
84=y^2
So, y=sqrt(84) or 2 sqrt(21).
Now, using the pythagorean theorem, we get
4^2+2sqrt(21)^2=x^2
100=x^2
x=10
<em>kx</em> + <em>z</em> = 3 means <em>z</em> = 3 - <em>kx</em>. Substitute this into the first two equations:
<em>x</em> + <em>y</em> + 3 (3 - <em>kx</em>) = 10 ==> (1 - 3<em>k</em>) <em>x</em> + <em>y</em> = 1
-4<em>x</em> + 3<em>y</em> + 5 (3 - <em>kx</em>) = 7 ==> (-4 - 5<em>k</em>) <em>x</em> + 3<em>y</em> = -8
Multiply through the first equation by -3 :
-3 ((1 - 3<em>k</em>) <em>x</em> + <em>y</em>) = -3 (1) ==> (-3 + 9<em>k</em>) <em>x</em> - 3<em>y</em> = -3
Add this to the second equation to eliminate <em>y</em> :
((-3 + 9<em>k</em>) <em>x</em> - 3<em>y</em>) + ((-4 - 5<em>k</em>) <em>x</em> + 3<em>y</em>) = -3 + (-8)
(-7 + 4<em>k</em>) <em>x</em> = -11
Normally, you would solve for <em>x</em> by dividing both sides by -7 + 4<em>k</em>. But you can't do that if this turns out to be equal to 0, which happens for
-7 + 4<em>k</em> = 0 ==> <em>k</em> = 7/4
Let the side of the square base be x, and the height of the box be h.
<span>The material of the base is x^2, and the material of the four sides is 4xh. </span>
<span>4000 = hx^2 </span>
<span>h = 4000/x^2 </span>
<span>The total material is </span>
<span>M = x^2 + 4x(4000/x^2) = x^2 + 16000/x </span>
<span>Take the first derivative of M and set equal to 0. </span>
<span>M' = 2x - 16000/x^2 = 0 </span>
<span>Multiply by x^2: </span>
<span>2x^3 = 16000 </span>
<span>x^3 = 8000 </span>
<span>x = 20; h = 10; M = 1200</span>
Answer:
Yes. If it has one variable and not exponential the solution is 1.
If is one variable and to power of 2 it is quadratic and two solutions.
If it two variable with no power it is simultaneous and with 2 solutions. E.t.c
Step-by-step explanation:
