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Masteriza [31]
3 years ago
11

I'm completely lost on this question please help

Mathematics
2 answers:
Lunna [17]3 years ago
8 0
First, note that y≠0 and y≠4 because that would make the denomenators 0 which is undefined

 
we got to get rid of fractions
common denomenator is y(y-4)
multiply both sides by y(y-4)
2y+y-4=y(y-1)
3y-4=y²-y
minus 3y both sides
-4=y²-4y
add 4 both sides
0=y²-4y+4
factor
what 2 numbers multiply to get 4 and add to get -4?
-2 and -2
0=(y-2)(y-2)
set to zero

y-2=0
y=2
no extranious roots


y=2 is the solution
solmaris [256]3 years ago
6 0
Multiply the numerators by "y" which yields:
(2y) / (y-4)  +1 = (y^2 -y) / (y-4)
(2y) / (y-4)  - (y^2 -y) / (y-4) = -1

(2y) - (y^2 -y) / (y-4) = -1

(2y) - (y^2 -y) = -y +1

-y^2 +2y -y +y = 1

-y^2 +2y -1 = 0

Multiplying by -1

y^2 -2y +1 = 0

(y -1) * (y - 1) = 0

x = 1
x= 1

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a line is perpendicular to y - 5 = -1/4(x + 8) and goes through the point (-1,2). What is the lines y-intercept?
lisabon 2012 [21]

Answer:

y = 4x + 6

Step-by-step explanation:

Turn the equation we are given into slope-intercept form.

y - 5 = -1/4(x + 8)

y - 5 = -1/4x - 2

y = -1/4x + 3

The slope of a perpendicular line is the opposite reciprocal of the original line.

-1/4 -> 4/1 -> 4

Find the new y-intercept using the point given.

y = 4x + b

2 = 4(-1) + b

2 = -4 + b

6 = b

Fill in everything we solved for.

y = 4x + 6

Best of Luck!

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