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2 years ago

Find the ninth term of the sequence sprt(5), sprt(10), 2 sprt(5)

Mathematics

2 answers:

Marina86 [1]2 years ago

6 0

Formula for this is (sqrt(2)^(n-1))*sqrt(5) such that n is the term number
So sqrt(2)^8(sqrt(5))
The answer is (B) 16sqrt(5)

saw5 [17]2 years ago

5 0

Answer:

16sqrt5

Step-by-step explanation:

Notice that the next term is the previous term multiplied by sqrt2.

So we can take sqrt5 and multiply it by sqrt2, 8 times to get the ninth term.

sqrt2 ^8 = 16.

So 16sqrt5

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Can someone help me fill in the blank

Elden [556K]

Answer:

integer

Step-by-step explanation:

The greatest integer function produces the greatest integer less than or equal to x

8 0

3 years ago

Read 2 more answers

Find 15.75 ÷ 0.25 using a Giant One.

MA_775_DIABLO [31]

15.75 divided by 0.25

In every 1 whole number, there are 4 of 0.25

Now we have 15 as whole number so simply multiply 15 x 4

15 * 4 = 60, there are 60 pieces of .025s in 15.

0.75 has 3 0.25s

Now, let’s add 60 + 3 = 63, the answer is 63.

There are 63 pieces of 0.25 in 15.75.

15.75 / 0.25

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2 years ago

Ignore the stuff around it ,could someone explain me this?

Ierofanga [76]

Answer:

The lines blue and green are perpendicular

Step-by-step explanation:

we know that

If two lines are perpendicular, then their slopes are opposite reciprocal (the product of their slopes is -1)

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

step 1

Find the slope of the blue line

we have the points

(-1,-3) and (0,3)

substitute

$m=\frac{3+3}{0+1}$

$m=\frac{6}{1}=6$

step 2

Find the slope of the red line

we have the points

(3,-3) and (4,2)

substitute

$m=\frac{2+3}{4-3}$

$m=\frac{5}{1}=5$

step 3

Find the slope of the green line

we have the points

(-4,-1) and (2,-2)

substitute

$m=\frac{-2+1}{2+4}$

$m=-\frac{1}{6}$

step 4

Compare the slopes

Blue line ----> $m=6$

Red line ----. $m=5$

Green line ---> $m=-\frac{1}{6}$

The slope of the blue line and the green line are opposite reciprocal ( their product is equal to -1)

therefore

The lines blue and green are perpendicular

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3 years ago

find the perimeter and diagonal of a square whose area is equal to the area of a rectangle whose length is 9m and breadth is 4m

aalyn [17]

$Area\ of\ a\ rectangle:A_{\fbox{ }}=9m\times4m=36m^2\\\\a-side\ of\ a\ square\\\\Area\ of\ a\ square:A_{\fbox{}}=a^2\\\\A_{\fbox{ }}=A_{\fbox{}}\Rightarrow a^2=36m^2\Rightarrow a=\sqrt{36m^2}\Rightarrow a=6m\\\\Perimeter\ of\ the\ square:P=4a\Rightarrow P=4\times6m=\boxed{24m}\\\\Diagonal\ of\ the\ square:d=a\sqrt2\Rightarrow d=\boxed{6\sqrt2\ m}$

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3 years ago

Is this a linear function ?<br><img src="https://tex.z-dn.net/?f=y%20%3D%20%20-%203%20%5E%7B2%7D%20%20%2B%202" id="TexFormula1"

Slav-nsk [51]

No its not a linear function i think

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3 years ago

Find the ninth term of the sequence sprt(5), sprt(10), 2 sprt(5)​

Find the ninth term of the sequence sprt(5), sprt(10), 2 sprt(5)