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3 years ago

In addition to talking to other doctors remotely, telegraphy technology?

Computers and Technology

1 answer:

telo118 [61]3 years ago

3 0

Answer:

Option A

Explanation:

it lets the doctors to talk to their patients about their concerns and the doctor will try to help them or make a diagnosis using the information given by the patient.

No one should self diagnose using the internet.

sometimes in order to confirm their diagnosis the doctor will require you to take certain tests,thus telehealth does not eliminate the need to visit the doctor.

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*hacked*

galben [10]

Hey Litz06,

Sorry that happened to you.

Try changing your password to something complicated so it’s more secure.

5 0

3 years ago

Levi wants to run 5 commands sequentially, but does not want to create a shell script. He knows that each command is going to ta

disa [49]

Levi can use the bash command to type all the commands on the same line to type one after the other character without requiring input.

Explanation:

He wants to run five commands. For one command it will take exactly 20 minutes. So it will take one hour forty minutes.
To type all of the commands on the same line Levi should use the bash command. For inserting the bash command Levi should use backslash \ as the last character of the line.

6 0

2 years ago

Match the term to its correct defintion

emmasim [6.3K]

Answer:

View Base tables: Virtual table based on a SELECT query

CREATE VIEW statement: Data definition command that stores the query specification in the data dictionary

DROP VIEW statement: Data definition command that removes the query specification in the data dictionary

Explanation:

Views are virtual tables, which can be created by select queries using the real database tables.

Creating and dropping views can be done by the CREATE VIEW and DROP VIEW statements.

CREATE VIEW syntax:

CREATE VIEW view_name AS

SELECT column1, column2, ...

FROM table_name

WHERE condition;

DROP VIEW syntax:

DROP VIEW view_name;

5 0

2 years ago

There are n poor college students who are renting two houses. For every pair of students pi and pj , the function d(pi , pj ) ou

Nuetrik [128]

Answer:

Here the given problem is modeled as a Graph problem.

Explanation:

Input:- n, k and the function d(pi,pj) which outputs an integer between 1 and n2

Algorithm:-We model each student as a node. So, there would be n nodes. We make a foothold between two nodes u and v (where u and v denote the scholars pu and pv respectively) iff d(pu,pv) > k. Now, Let's call the graph G(V, E) where V is that the vertex set of the graph ( total vertices = n which is that the number of students), and E is that the edge set of the graph ( where two nodes have edges between them if and only the drama between them is bigger than k).

We now need to partition the nodes of the graph into two sets S1 and S2 such each node belongs to precisely one set and there's no edge between the nodes within the same set (if there's a foothold between any two nodes within the same set then meaning that the drama between them exceeds k which isn't allowed). S1 and S2 correspond to the partition of scholars into two buses.

The above formulation is akin to finding out if the graph G(V,E) is a bipartite graph. If the Graph G(V, E) is bipartite then we have a partition of the students into sets such that the total drama <= k else such a partition doesn't exist.

Now, finding whether a graph is bipartite or not is often found using BFS (Breadth First algorithm) in O(V+E) time. Since V = n and E = O(n2) , the worst-case time complexity of the BFS algorithm is O(n2). The pseudo-code is given as

PseudoCode:

// Input = n,k and a function d(pi,pj)

// Edges of a graph are represented as an adjacency list

1. Make V as a vertex set of n nodes.

2. for each vertex u ∈ V

$\rightarrow$ for each vertex v ∈ V

$\rightarrow\rightarrow$ if( d(pu, pj) > k )

$\rightarrow\rightarrow\rightarrow$ add vertex u to Adj[v] // Adj[v] represents adjacency list of v

$\rightarrow\rightarrow\rightarrow$ add vertex v to Adj[u] // Adj[u] represents adjacency list of u

3. bool visited[n] // visited[i] = true if the vertex i has been visited during BFS else false

4. for each vertex u ∈ V

$\rightarrow$ visited[u] = false

5. color[n] // color[i] is binary number used for 2-coloring the graph

6. for each vertex u ∈ V

$\rightarrow$ if ( visited[u] == false)

$\rightarrow\rightarrow$ color[u] = 0;

$\rightarrow\rightarrow$ isbipartite = BFS(G,u,color,visited) // if the vertices reachable from u form a bipartite graph, it returns true

$\rightarrow\rightarrow$ if (isbipartite == false)

$\rightarrow\rightarrow\rightarrow$ print " No solution exists "

$\rightarrow\rightarrow\rightarrow$ exit(0)

7. for each vertex u ∈V

$\rightarrow$ if (color[u] == 0 )

$\rightarrow\rightarrow$ print " Student u is assigned Bus 1"

$\rightarrow$ else

$\rightarrow\rightarrow$ print " Student v is assigned Bus 2"

BFS(G,s,color,visited)

1. color[s] = 0

2. visited[s] = true

3. Q = Ф // Q is a priority Queue

4. Q.push(s)

5. while Q != Ф {

$\rightarrow$ u = Q.pop()

$\rightarrow$ for each vertex v ∈ Adj[u]

$\rightarrow\rightarrow$ if (visited[v] == false)

$\rightarrow\rightarrow\rightarrow$ color[v] = (color[u] + 1) % 2

$\rightarrow\rightarrow\rightarrow$ visited[v] = true

$\rightarrow\rightarrow\rightarrow$ Q.push(v)

$\rightarrow\rightarrow$ else

$\rightarrow\rightarrow\rightarrow$ if (color[u] == color[v])

$\rightarrow\rightarrow\rightarrow\rightarrow$ return false // vertex u and v had been assigned the same color so the graph is not bipartite

}

6. return true

3 0

3 years ago

IT professionals should help to protect users’ personal information, such as bank account information or Social Security numbers

sesenic [268]

To prevent theft of account information, identity theft, money, important passwords, and personal information.

Hope it helps ❤️

8 0

3 years ago

Read 2 more answers