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Olenka [21]
4 years ago
7

Jenny earned a 77 on her most recent test. Jenny’s score is no less than 5 points greater than 4/5 of Terrance’s score. If t rep

resents Terrance’s score, which inequality represents the situation?

Mathematics
2 answers:
hram777 [196]4 years ago
7 0
77 \geq 5 + 4/5t
jasenka [17]4 years ago
6 0

Answer:    

The situation is represented by the following inequality :

\bf 77\geq \frac{4}{5}\cdot t+ 5

Step-by-step explanation:

Score earned by Jenny on her most recent test = 77

Let the Terrance's score is represented by t

\frac{4}{5}\text{ of the Terrance's score is = }\frac{4}{5}\cdot t

If Terrance's score is 5 points greater then the points earned by Terrance's in the test is represented by :

\bf\frac{4}{5}\cdot t+ 5.......(1)

Now, according to the given condition in the question , Jenny's score is not less than the score represented by (1)

⇒ Jenny's score is greater than equal to the score represented by (1)

Hence, The situation is represented by the following inequality :

\bf 77\geq \frac{4}{5}\cdot t+ 5

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Use properties of operations to determine whether or not the expressions (x + 10) + x + 9 and 2(x + 7) + 5 are
Anna35 [415]

Answer:

The expressions are equivalent.

Step-by-step explanation:

We can simplify each expression and compare the results.

(x + 10) + x + 9 = x + 10 + x + 9 = 2x + 19

2(x + 7) + 5 = 2x + 14 + 5 = 2x + 19

2x + 19 = 2x + 19

Answer: The expressions are equivalent.

7 0
3 years ago
Find the angle between u = (8.- 3) and v = (-3,- 8) Round to the nearest tenth of a degree.
Nimfa-mama [501]

Answer:

<h2>90°</h2>

Step-by-step explanation:

First you must calculate the module or the magnitude of both vectors

The module of u is:

|u|=\sqrt{(8)^2 + (-3)^2} \\\\|u|=\sqrt{64 + 9}\\\\|u|=8.544

The module of v is:

|v|=\sqrt{(-3)^2 + (-8)^2} \\\\|u|=\sqrt{9 + 64}\\\\|u|=8.544

Now we calculate the scalar product between both vectors

u*v = 8*(-3) + (-3)*(-8)\\\\u*v = -24+ 24=0

Finally we know that the scalar product of two vectors is equal to:

u*v = |u||v|*cos(\theta)

Where \theta is the angle between the vectors u and v. Now we solve the equation for \theta

0 = 8.544*8.544*cos(\theta)\\\\0 = cos(\theta)\\\\\theta= arcos(0)\\\\\theta=90\°

the answer is 90°

Whenever the scalar product of two vectors is equals to zero it means that the angle between them is 90 °

5 0
4 years ago
Read 2 more answers
50 points! Please help this is due soon. Correct answer will get brainliest. Random answers will be reported
Murrr4er [49]

(╯°□°)╯︵ ┻━┻(╯°□°)╯︵ ┻━┻

7 0
3 years ago
The equation of a circle is given below.
Nataliya [291]

Answer:

(h,k) = (32,-4)

r = 32

Step-by-step explanation:

The general equation for a circle is given by:

(x-h)^2+(y-k)^2=r^2   (1)

where (h,k) is the center of the circle and r is the radius.

You have the following equation:

x^2+(y+4)^2=64x   (2)

You first need to complete squares in order to obtain an equation of the form (1). Thus, you have that the second term must be in a perfect square trinomial:

2b = 64

b = 32

Then, you have to sum 32^2 and also subtract the same number in the expression (2):

x^2-64x+(y+4)^2=0\\\\(x^2-64x+32^2)+(y+4)^2-32^2=0\\\\(x-32)^2+(y+4)^2=32^2

you compare the last result with expression (1) and obtain that the raiuds of the circle is r = 32

Furthermore, the center of the circle is (h,k) = (32,-4)

5 0
4 years ago
Find the coordinates of the midpoint M and the distance between P(-6, -1) and Q(1,2). Round to the nearest
nlexa [21]

Answer:

  • M(-3.5, 0.5)

Step-by-step explanation:

<u>Given points:</u>

  • P(-6, -1) and Q(1,2)

<u>Midpoint by using midpoint formula:</u>

  • x = (-6 + 1)/2 = -3.5
  • y = (-1 + 2)/2 = 0.5
  • M(-3.5, 0.5)
4 0
3 years ago
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