Answer:
rolling a number cube with sides labeled 1 through 6 and tossing a coin.
Step-by-step explanation:
We will resolve each statement to determine the events that has exactly 12 possible outcomes.
N = number of possible outcomes for a cube
Nc = number of possible outcomes for a coin
Nca = number of possible outcomes for the cards
i. rolling a number cube with sides labeled 1 through 6 and then rolling the number cube again
Nt = N × N
N = 6 ( cube has 6 possible outcomes and its rolled twice)
Nt = 6 × 6 = 36
ii. tossing a coin and randomly choosing one of 4 different cards.
Nt = Nc × Nca
Nc = 2 ( coin has two outcomes)
Nca = 4 ( 4 possible cards )
B = 2 × 4 = 8
iii. rolling a number cube with sides labeled 1 through 6 and tossing a coin.
N = N × Nc
N = 6 ( cube has 6 possible outcomes)
Nc = 2 (coin has two faces)
N = 6 × 2 = 12 (correct)
Iv. tossing a coin 6 times.
N = Nc^6
Nc = 2
N = 2^6 = 64
Therefore, the correct answer is iii.
rolling a number cube with sides labeled 1 through 6 and tossing a coin.
In thirty months you should have 5,250.00
There are 4 teams in total and each team has 7 members. One of the team will be the host team.
Tournament committee will be made from 3 members from the host team and 2 members from each of the three remaining teams. Selecting the members for tournament committee is a combinations problem. We have to select 3 members out 7 for host team and 2 members out of 7 from each of the remaining 3 teams.
So total number of possible 9 member tournament committees will be equal to:

This is the case when a host team is fixed. Since any team can be the host team, there are 4 possible ways to select a host team. So the total number of possible 9 member tournament committee will be:

Therefore, there are 2917215 possible 9 member tournament committees
16.76 rounds off to 17
After the dot if it’s 1-4 then they it would’ve been 15
5-9 is 17
Y - x = 6
y + 2x = 57
2y - 2x =12
y + 2x = 57
∴3y = 69
y = 23
23 - x = 6
-x = -17
x =17
large van = 23
small van = 17