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prohojiy [21]
4 years ago
10

bruce is playing with a set of base-ten blocks. he has 65 ten-blocks and 7 one-blocks. what is the value of his blocks

Mathematics
1 answer:
Oksi-84 [34.3K]4 years ago
5 0
The 65 tens blocks can be solved by doing 65x10 which is 650.  the 7 ones blocks can be solved by 1x7  which is 7 so you then add up 650 and 7 to get a grand total of 657
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What is the solution to y-7>3+2y
Alex17521 [72]

Solving:

-7 + y = 3 + 2y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-2y' to each side of the equation.

-7 + y + -2y = 3 + 2y + -2y

Combine like terms: y + -2y = -1y

-7 + -1y = 3 + 2y + -2y

Combine like terms: 2y + -2y = 0

-7 + -1y = 3 + 0

-7 + -1y = 3

Add '7' to each side of the equation.

-7 + 7 + -1y = 3 + 7

Combine like terms: -7 + 7 = 0

0 + -1y = 3 + 7

-1y = 3 + 7

Combine like terms: 3 + 7 = 10

-1y = 10

Divide each side by '-1'.

y = -10

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Step-by-step explanation:

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John di Silvestre obtained a loan to buy a cello for $8,400. He pays 12% exact interest on the loan for 146 days. What is the am
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Step-by-step explanation:

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What is the factored form of the expression?<br><br> d^2 = 36d + 324
Aleonysh [2.5K]

Answer:

(x-43.45)(x+7.45)=0.

Step-by-step explanation:

We have the quadratic equation d^{2}=36d+324 i.e. d^{2}-36d-324=0

Now, the roots of the quadratic equation ax^{2}+bx+c=0 are given by x=\frac{-b\pm \sqrt{b^{2}-4ac}}{2a}

So, from the given equation, we have,

a = 1, b =-36 , c = -324.

Substituting the values in x=\frac{-b\pm \sqrt{b^{2}-4ac}}{2a}, we get,

x=\frac{36\pm \sqrt{(-36)^{2}-4\times 1\times (-324)}}{2\times 1}

i.e. x=\frac{36\pm \sqrt{1296+1296}}{2}

i.e. x=\frac{36\pm \sqrt{2592}}{2}

i.e. x=\frac{36\pm 50.9}{2}

i.e. x=\frac{36+50.9}{2}  and i.e. x=\frac{36-50.9}{2}

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i.e. x = 43.45 and x = -7.45

Hence, the factored form of the given expression will be (x-43.45)(x+7.45)=0.

4 0
3 years ago
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