2 years ago

The surface area of this cylinder to the nearest integer is

Mathematics

1 answer:

Nutka1998 [239]2 years ago

6 0

Answer:

Option C. $132\ in^{2}$

Step-by-step explanation:

we know that

The surface area of cylinder is equal to

$SA=2\pi r^{2} +\pi Dh$

we have

$D=6\ in$

$r=6/2=3\ in$

$h=4\ in$

substitute

$SA=2\pi (3^{2}) +\pi (6*4)=42\pi\ in^{2}=132\ in^{2}$

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