Question

The surface area of this cylinder to the nearest integer is

Answer 1

Answer:

Option C. $132\ in^{2}$

Step-by-step explanation:

we know that

The surface area of cylinder is equal to

$SA=2\pi r^{2} +\pi Dh$

we have

$D=6\ in$

$r=6/2=3\ in$

$h=4\ in$

substitute

$SA=2\pi (3^{2}) +\pi (6*4)=42\pi\ in^{2}=132\ in^{2}$