Answer:
7(3a + 5)
Step-by-step explanation:
Rewrite 21 as 7 · 3
Rewrite 35 as 7 · 5
Therefore,
⇒ 21a + 35 = 7 · 3a + 7 · 5
Factor out common term 7:
⇒ 7 · 3a + 7 · 5 = 7(3a + 5)
Y= 4 - 4/5x all you have to do is make it go up 4 from 0 and either go down 4 and go right 5 or up 4 and to the left 5... hope this helped!
Answer:
One 50$, one 5$, and four 1$ bills
Answer:
There may be 1 or 3 tricycles in the parking lot.
Step-by-step explanation:
Since at any point in time, there could be bicycles, tricycles, and cars in the school parking lot, and today, there are 53 wheels in total, if there are 15 bicycles, tricycles, and cars in total, to determine how many tricycles could be in the parking lot, the following calculation must be performed:
13 x 4 + 1 x 3 + 1 x 2 = 57
11 x 4 + 1 x 3 + 3 x 2 = 53
10 x 4 + 3 x 3 + 2 x 2 = 53
8 x 4 + 5 x 3 + 2 x 2 = 51
10 x 2 + 1 x 3 + 4 x 4 = 39
9 x 3 + 1 x 2 + 5 x 4 = 49
Therefore, there may be 1 or 3 tricycles in the parking lot.
Answer: 10.8-62.91t+38.8n
Step-by-step explanation:
