Let y = 12 e^2x
e^2x = y/12
Taking
[email protected]ln e^2x = ln (y/12)
2x = ln (y/12)
x = (1/2) ln (y / 12)
so the inverse h-1(x) = (1/2) ln ( x / 12)
D, because 1/4 is equivalent to 4/12 and 7/12+4/12=11/12 which is equivalent to 5/6
5t = 25+2r
t = (25+2r)/5 or
t = 5 + (2/5)r
Answer:
Exactly one solution
Explanation:
The first step we need to take to find the answer is to find the value of y.
7(y+3)=5y+8
Expand the parentheses
7y+21=5y+8
Subtract both sides by 21
7y+21-21=5y+8-21
7y=5y-13
Subtract both sides by 5y
7y-5y=5y-13-5y
2y=-13
Divide both sides by 2
2y/2=-13/2
y=-6.5
Now, we plug y back into the original equation.
7(y+3)=5y+8
7(-6.5+3)=5(-6.5)+8
Expand the parentheses
-45.5+21=-32.5+8
-24.5=-24.5
Because both sides of the equation is equal and the equation is true, we can conclude that the equation has one solution.
I hope this helps!
