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Yuliya22 [10]
3 years ago
5

What is the volume of a rectangular prism whose edges measure 3 ft, 3 ft, and 2 ft?

Mathematics
1 answer:
Mrac [35]3 years ago
6 0
Volume of rectangular prism = l * b * h
v = 3 * 3 * 2
v = 18

In short, Your Answer would be 18 ft³

Hope this helps!
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Find the vertex of the graph of f(x)=-4(x-1)(x+5)
madreJ [45]

The vertex of the graph is (h, k) = (- 2, 36).

<h3>How to find analytically the vertex of a quadratic equation</h3>

In this question we have a quadratic equation of the form f(x) = a · (x - r₁) · (x - r₂) and we need to transform the expression into its vertex form of determine the coordinates of the vertex. First, we need to exprand the expression:

f(x) = - 4  · (x - 1) · (x + 5)

f(x) = - 4 · (x² + 4 · x - 5)

f(x) = - 4 · x² - 16 · x + 20

Now we proceed to complete the square:

f(x) = - (4 · x² + 16 · x - 20)

- f(x) = 4 · x² + 16 · x - 20

- f(x) = (2 · x)² + 8 · (2 · x) - 20

- f(x) + 36 = (2 · x)² + 8 · (2 · x) + 16

- f(x) + 36 = (2 · x + 4)²

- f(x) + 36 = 4 · (x + 2)²

f(x) - 36 = - 4 · (x + 2)²

The vertex of the graph is (h, k) = (- 2, 36).

To learn more on quadratic equations: brainly.com/question/17177510

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7 0
1 year ago
HELP ME PLESA IM DESPO PAKJDCD PLS HELP
WARRIOR [948]

Answer:

144 cm²

Step-by-step explanation:

A prism's surface has 2 triangles & 3 rectangles.

In both the triangles , length of :

Perpendicular = 4 cm

Base = 6 cm

So , Area of both triangles = 2(\frac{1}{2} * Base * Perpendicular) = 2(\frac{1}{2}* 6 * 4) = 24 cm^2

In the 3 rectangles ,

Length = 8 cm

Width = 5 cm

So , Area of the rectangles = 3( Length * Width) = 3(8 * 5) = 120 cm^2

Hence the total surface area of the prism is = 120 + 24 =144 cm²

6 0
2 years ago
Is the following correspondence a function
GenaCL600 [577]
No, because element b has 2 correspondents.
7 0
3 years ago
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Land's Bend sells a wide variety of outdoor equipment and clothing. The company sells both through mail order and via the intern
nata0808 [166]

Answer:

−35.713332 ; 0.313332

Step-by-step explanation:

Given that:

Sample size, n1 = 11

Sample mean, x1 = 79

Standard deviation, s1 = 18.25

Sample size, n2 = 18

Sample mean, x2 = 96.70

Standard deviation, s2 = 20.25

df = n1 + n2 - 2 ; 11 + 18 - 2 = 27

Tcritical = T0.01, 27 = 2.473

S = sqrt[(s1²/n1) + (s2²/n2)]

S = sqrt[(18.25^2 / 11) + (20.25^2 / 18)]

S = 7.284

(μ1 - μ2) = (x1 - x2) ± Tcritical * S

(μ1 - μ2) = (79 - 96.70) ± 2.473*7.284

(μ1 - μ2) = - 17.7 ± 18.013332

-17.7 - 18.013332 ; - 17.7 + 18.013332

−35.713332 ; 0.313332

3 0
2 years ago
PLS HELP WILL GIVE BRIANLEST.
satela [25.4K]

Answer:

In this equation, let "x" equal the rate at which the tub will be filled. The tub holds 32 gallons, which will be one half of the equation. The tub already contains 12 gallons, so this will be half of the other side of the equation. The rate is "x" gallons per minute, and the time it required was 5 minutes, so this would be "5x". Placing all these parts together gives an equation of (32 = 5x + 12) gallons per minute dispensed.

6 0
3 years ago
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