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QveST [7]
3 years ago
11

How many solutions does the following system have? y=x-2 -x+y=-5

Mathematics
1 answer:
leva [86]3 years ago
6 0
To find how many solution our system has, we are going to find the slope of each equation.
y=x-2 equation (1)
-x+y=-5 equation (2)
To find the slope, we are going to express both equations in the form: y=mx+b
where
m is the slope

Notice that equation (1) is already in the form y=mx+b; from equation (1) we can infer that m=1

To express equation (2) in the form y=mx+b, we are going to add x to both sides of the equation: 
-x+x+y=x-5
y=x+5
Now, we can infer that the slope of equation (2) is m=1. Since both equations have the same slope, we are dealing with parallel lines; parallel lines don't intercept, so the system has no solutions.

We can conclude that the correct answer is  the first choice: <span>no solutions</span>

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Answer:

A. 2/3

Step-by-step explanation:

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Ierofanga [76]

Answer:

24002

Step-by-step explanation:

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= 24002 (rounded to the nearest whole number)

Hope this helped!

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2 years ago
A string passing over a smooth pulley carries a stone at one end. While its other end is attached to a vibrating tuning fork and
nasty-shy [4]

Answer:

correct option is C)  2.8

Step-by-step explanation:

given data

string vibrates form =  8 loops

in water loop formed =  10 loops

solution

we consider  mass of stone = m

string length = l

frequency of tuning = f

volume = v

density of stone = \rho

case (1)  

when 8 loop form with 2 adjacent node is \frac{\lambda }{2}

so here

l = \frac{8 \lambda _1}{2}      ..............1

l = 4 \lambda_1\\\\\lambda_1 = \frac{l}{4}

and we know velocity is express as

velocity = frequency × wavelength   .....................2

\sqrt{\frac{Tension}{mass\ per\ unit \length }}   =   f × \lambda_1

here tension = mg

so

\sqrt{\frac{mg}{\mu}}   =   f × \lambda_1     ..........................3

and

case (2)  

when 8 loop form with 2 adjacent node is \frac{\lambda }{2}

l = \frac{10 \lambda _1}{2}      ..............4

l = 5 \lambda_1\\\\\lambda_1 = \frac{l}{5}

when block is immersed

equilibrium  eq will be

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T + v × \rho × g = mg

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T = v × \rho - v × \rho × g    

from equation 2

f × \lambda_2 = f  × \frac{1}{5}  

\sqrt{\frac{v\rho _{stone} g - v\rho _{water} g}{\mu}} = f \times \frac{1}{5}     .......................5

now we divide eq 5 by the eq 3

\sqrt{\frac{vg (\rho _{stone} - \rho _{water})}{\mu vg \times \rho _{stone}}} = \frac{fl}{5} \times \frac{4}{fl}

solve irt we get

1 - \frac{\rho _{stone}}{\rho _{water}}  = \frac{16}{25}

so

relative density \frac{\rho _{stone}}{\rho _{water}} = \frac{25}{9}

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3 0
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tino4ka555 [31]

x = 7

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nlexa [21]

Answer:

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Step-by-step explanation:

if it's wrong im sorry-

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