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Blababa [14]
3 years ago
13

F(x) = x² + x ² x ² + x + 2

Mathematics
1 answer:
Oduvanchick [21]3 years ago
8 0

Answer:

y=x^4+x^2+x+2

Step-by-step explanation:

y=x2+x2x2+x+2

y=x4+x2+x+2

Click on picture to get full view!!

if you have any questions let me know!

Hope this helps! If so please mark brainliest and rate/heart to help my account if it did!!

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Is the point on the line ?
Oxana [17]

Answer:

i think the answer is no i used tge desmo graphing calculator and tht point wasnt on it

3 0
2 years ago
In the diagram below, ST is parallel to QR. angle P is 40 degrees, and QST is 2R+8. Find the measure of STR in degrees.
lozanna [386]

Answer:

148º

Step-by-step explanation:

Use the information given:

  • The measure of a straight line is 180º. So angle PST=180-(2R+8)
  • Since ST and QR are parallel, angle PST=angle PQR. Now, angle PQR=180-(2R+8)
  • The sum of a triangle's interior angles is 180º. So 40+180-2R-8+R=180º.
  • Combine like terms, 212-R=180
  • Subtract, -R=-32
  • Convert to positive, R=32º

With R=32º, we can find angle QST and PQR. Angle QST=2(32)+8=64+8=72º. So angle PQR=180º-72º=108º. The sum of a quadrilateral's interior angles is 360º:

  • 32º+72º+108º+STR=360º
  • Combine like terms, 212º+STR=360º
  • Subtract, STR=148º
3 0
3 years ago
Convert the equation r = 12 sin theta to Cartesian coordinates. Describe the resulting curve.
VLD [36.1K]

Answer:

Step-by-step explanation:

Given that there is a polar equation as

r=12 sin \theta

This has to be converted into cartesian.

We know the conversion is

r^2 =x^2+y^2 \\tan \theta = \frac{y}{x}

Using this we can say that

sin^2 \theta = 1-cos^2 \theta \\= 1-\frac{1}{sec^2 \theta} \\=1-\frac{1}{1+tan^2 \theta} \\=1-\frac{1}{1+\frac{y^2}{x^2} } \\=1-\frac{x^2}{x^2+y^2} \\=\frac{y^2}{y^2+y^2}

\sqrt{x^2+y^2} =12(\frac{y}{\sqrt{x^2+y^2} } \\x^2+y^2 =12y\\x^2+y^2-12y+36 = 36\\x^2+(y-6)^2 = 6^2}

Circle with centre (0,6) and radius 6.

7 0
3 years ago
A researcher posts a newspaper advertisement offering $20 in exchange for participation in a short study. The researcher accepts
Alborosie

Answer:

C : VALID

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Give the equation of the circle that is tangent to the y-axis and Center is (-3,2).
joja [24]
The formula<span> for the </span>equation<span> of a </span>circle<span> is (x – h)</span>2+ (y<span> – k)</span>2<span> = r</span>2<span>, where (h, k) represents the coordinates of the </span>center<span> of the </span>circle<span>, and r represents the radius of the </span>circle<span>. If a </span>circle<span> is </span>tangent<span> to the x-</span>axis<span> at (</span>3,0), this means it touches the x-axis at that point. hope this helps

- Ava<3
8 0
3 years ago
Read 2 more answers
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