The correct answer that would best complete the given statement above would be this: A potential benefit of recruiting slow oxidative fivers for contraction before recruiting fast oxidative and fast glycolytic fibers might be because they are slower to respond, slow oxidative fibers must be stimulated first in order contract simultaneously with the faster fibers. Hope this answer helps.
Answer:
transformation is carried out by random uptake of DNA, and transduction by a bacterial virus
Explanation:
Transformation and transduction are two of the three processes bacteria uses in genetic recombination (the third being conjugation). As rightly stated in the question, both processes establish that DNA is the genetic material of most living organisms and they both involve transfer and expression of DNA from cell to cell.
However, both processes are different in the way they get the foreign DNA into the bacteria cell.
- Transformation involves the random uptake of foreign extracellular DNA by the host bacterial cell.
- Transduction involves the transfer of foreign DNA into a bacteria cell via a virus called BACTERIOPHAGE. N.B: A bacteriophage is a virus that infects a bacteria host.
Answer:
Chiasma
Explanation:
During meiosis, more precisely, prophase 1 homologous chromosomes connect in a process known as synapsis and form tetrad structure (four chromatides). Non-sister chromatids mayrecombine with their homologous partner which is known as crossing over, the process in which genetic variabilty is produced. These non-sister chromatids remain physically connected at the points of exchange known as chiasmata.
Explanation:
that is a basic punnett square so that should answer your question
