Answer:
B) Multicellular Simple gland
Explanation:
Exocrine Glands:Glands that secrete their products onto the apical(or epithelia) surface directly or via epithelial ducts or tubes that are connected to the apical surface. These Exocrine glands are composed of highly specialized epithelial cells..
Exocrine glands can either be branched or Unbranched based on the arrangement.
*Multicellular simple glands*:Glands that have an *unbranched duct* into which cells secrete. Each secretory portion empties separately on an epithelial surface.
Eukaryotic cells are theorized to have evolved from prokaryotes called the endosymbiotic theory. This explains that the most primitive eukaryotic cell engulfed a prokaryotic cell (by the process of phagocytosis) that is capable of cellular respiration and another prokaryotic cell that is capable of photosynthesis. These prokaryotic cells eventually became organelles and these organelles are the mitochondria and the chloroplast.
Glucose is the main provider of energy for the brain and the nervous system. Because the brain is so rich in nerve cells, or neurons, it is the most energy demanding organ, using one half of all the sugar energy in the body. Brain functions such as memory, thinking and learning are closely linked to glucose levels and how efficiently the brain uses this fuel source.
Verdade? Não tenho certeza.......
Answer:
D) B/b;S/s (x) b/b;s/s
Explanation:
Parent 1 : belted syndactylous sow
Since it is showing dominant phenotype for both the traits, it can either be BBSS or BbSs
Parent 2: unbelted cloven-hoofed
Since it is showing recessive phenotype for both the traits, it can only have bbss genotype
If we assume parent 1 to be BBSS all the resulting progeny with bbss will have dominant phenotype which is not the case.
If we assume parent 1 to be BbSs:
BbSs X bbss =
BbSs : belted syndactylous
bbSs : unbelted syndactylous
Bbss : belted cloven
bbss : unbelted cloven
The progeny will be produced in 1:1:1:1 ratio which means that each of them will make 25% of the population.
Hence, parent 1 will have BbSs genotype and parent 2 will have bbss genotype
