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Lana71 [14]
3 years ago
14

How do solve this problem

Mathematics
1 answer:
Tanzania [10]3 years ago
8 0
Multiply the first equation by 3
21x+15y=-6

Add this to the second equation
21x+15y=-6
-21x-15y=6
0+0=0

True

Final answer: Infinitely Many Solutions (they are coinciding lines)
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Using principle of mathematical induction prove that 6^-1 divisble by 5 .​
salantis [7]

I suppose the claim is 5 \mid 6^n - 1 for n\in\Bbb N.

When n=1, we have 6^1 - 1 = 6 - 1 = 5, and of course 5 divides 5.

Assume the claim holds for n=k, that 5 \mid 6^k - 1. We want to use this to show it holds for n=k+1, that 5 \mid 6^{k+1} - 1.

We have

6^{k+1} - 1 = \left(6^{k+1} - 6\right) + \left(6 - 1) = 6\left(6^k - 1\right) + 5

Since 5 \mid 6^k - 1, we can write 6^k - 1 = 5\ell for some integer \ell. Then

6^{k+1} - 1 = 6\cdot5\ell + 5 = 5(6\ell + 1)

which is clearly divisible by 5. QED

5 0
2 years ago
Which function is equivalent to y=3(x+2)^2+7
Ilia_Sergeevich [38]
3x+45 most u can simplify it
8 0
3 years ago
Mary took a math test and she got four questions incorrect and 21 correct. What percent did answer correctly?
AnnZ [28]

Answer:

84%

Step-by-step explanation:

21 correct + 4 wrong = 25 questions in total

\frac{21}{25} x 4 = \frac{84}{100}

\frac{84}{100} = 0.84

0.84 = 84%

6 0
3 years ago
Solve f (x)=3x+6 f(300)
sveta [45]

Answer:

f(300)=906

Step-by-step explanation:

f(x)=3x+6\\\\f(300)=3(300)+6\\\\f(300)=900+6\\\\\boxed{f(300)=906}

Hope this helps.

8 0
3 years ago
What is 22,000,000 in word form
Vlad1618 [11]
It is twenty-two million 
4 0
3 years ago
Read 2 more answers
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