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Andrej [43]
3 years ago
8

Given A(-3,6) and B(5,-6) find the distance and midpoint between each

Mathematics
2 answers:
bezimeni [28]3 years ago
8 0
AB=\sqrt{(x _{b}- x_{a})^2+(y _{b}-y _{a})^2    }=  \sqrt{(5-(-3))^2+(-6-6)^2}\\
 \sqrt{8^2+(-12)^2}= \sqrt{64+144} = \sqrt{208}=4 \sqrt{13}
xenn [34]3 years ago
7 0
14.42 is your distance formula 
(1,0) is the midpoint 
if you need the forma for distance it is x2-x1 squared + y2-y1 squared then square root it 
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Find the product of z1 and z2, where z1 = 7(cos 40° + i sin 40°) and z2 = 6(cos 145° + i sin 145°).
Oduvanchick [21]
For two complex numbers z_1=re^{i\theta}=r(\cos\theta+i\sin\theta) and z_2=se^{i\varphi}=s(\cos\varphi+i\sin\varphi), the product is

z_1z_2=rse^{i(\theta+\varphi)}=rs(\cos(\theta+\varphi)+i\sin(\theta+\varphi))

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Read 2 more answers
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