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Paraphin [41]
2 years ago
14

A forest is cut down to make room for a housing development. Which population is most likely to survive? A. raccoons, which can

eat a variety of foods B. woodpeckers that need to nest in a particular tree C. large predators that need to hunt over a wide area D. salamanders that hibernate in rotting logs
Biology
1 answer:
dmitriy555 [2]2 years ago
3 0
D. salamanders that hibernate in rotting logs

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The left side of the brain notices _____, while the right side grasps _____ quizlet
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<span>The left side of the brain notices details, while the right side grasps the bigger picture. That's the answer for the question that you provided.</span>
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3 years ago
Bacteria cells have a rigid cell ____ that gives it its shape
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wall

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In Drosophila, vestigial (partially formed) wings (vg) are recessive to normal long wings (vg+) and the gene for this trait is a
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Answer/ Explanation:

a. The genotype of a homozygous white eyed long winged female would be Vg+Vg+XrXr. We denote the white allele as recessive (r) because the XY male only has one copy and yet has red eyes, so the red eye trait (R) must be dominant. A homozygous red eyed vestigial winged male would have be VgVgXRY. The possible gametes for the female are Vg+Xr only. For the male, the possible gametes are VgXR or VgY

The attached punnett square shows the results of the cross. The females will all be Vg+VgXRXr. The males will all be Vg+VgXRY (must inherit Y from father). That means they will all  have normal length wings, the males will have white eyes and the females will have red eyes.

b. The F2 flies arise from intercrossing the F1, so the cross will be Vg+VgXRXr x Vg+VgXRY. The possible gametes for the mother are: Vg+XR, Vg+Xr, VgXR or VgXr. The possible gametes for the father are Vg+Xr

, Vg+Y

, VgXr

, VgY

. The attached punnet square shows this cross. The ratio of the phenotypes will be 6:6:2:2, or 3:3:1:1 (long-winged red eye: long-winged white eye: vestigial wing red eye: vestigial wing white eye), genotypes shown in the attachment.

c. F1 cross back to the mother would be Vg+VgXRY x Vg+Vg+XrXr. The genotypes are shown in the attached punnet square. The offspring will all be long-winged with white eyes. The F1 to the father would be Vg+VgXRXr x VgVgXRY. The ratio would be 3:3:1:1 long-winged red eye: long-winged white eye: vestigial wing red eye: vestigial wing white eye

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7 0
3 years ago
While tuning a guitar, you realize one of the strings is not the right thickness. The pitch needs to be higher in order for the
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Answer is c hope this helps
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Answer #7 and will mark brainliest
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