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butalik [34]
3 years ago
15

Given that ∠A≅∠B , Gavin conjectured that ∠A and ∠B are complementary angles.

Mathematics
2 answers:
Trava [24]3 years ago
8 0

i just took the test answer is B hope that helped!

Katyanochek1 [597]3 years ago
3 0
<span>A counterexample is a special kind of example that disproves a statement or proposition.

Given that </span><span>∠A is congruent to ∠B, this means that the measure of angle A is equal to the measure of angle B.

Two angles are said to be complementary if their sum is 90 degrees.

Consider, </span>m∠A=25° and m∠B=25°, clearly, ∠A≅∠B, but m∠A + <span>m∠B = 25° + 25°</span> = 50<span>°.

Thus, </span><span>∠A≅∠B , but ∠A and ∠B are not complementary angles.</span>
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What is the equation of the line whose slope is 1/3 and y-intercept is -4?
faltersainse [42]

Answer:

y=1/3x-4

Step-by-step explanation:

the slope-intercept format of the line is y=mx+b, where m is the slope and b is the y intercept.

we are given the slope (1/3) and the y intercpet (-4).

substitute the numbers into the equation

y=1/3x-4

the answer is y=1/3x-4

hope this helps!

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3 years ago
In many cases the Law of Sines works perfectly well and returns the correct missing values in a non-right triangle. However, in
Minchanka [31]

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Step-by-step explanation:

7 0
2 years ago
Given two angles that measure 50 degrees and 80 degrees and side that measures 4 feet, how many triangles, if any, can be constr
kirza4 [7]
The angles are the only constraint here that counts.  If one of the three interior angles of a supposed triangle is 50 degrees and another is 80 degrees, then the third angle must be 50 degrees.  Thus, we have a 50-50-80 triangle, which is isosceles though not a right triangle.  If 4 feet is a measure of one of the equal sides of a supposed triangle, then obviously the adjacent side also has measure 4 ft.

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3 0
3 years ago
Which of the following expressions are factors of 25x^3−75x^2−9x+27?
Natali [406]

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4 0
3 years ago
amirah ,who is at a point P ,observes a boat at pont B 1200m from P in direction 047 degrees. The boat is moving due north of B
Luda [366]

Answer:

  about 2.81 km/h

Step-by-step explanation:

It can be useful to draw a diagram.

The lines pointing to due north from points B and P are parallel, so the angle BCP and the bearing of point C from P are the same, 30°. The angle BPC will be the difference of bearings of B and C at P, so is 47-30=17°. This is enough information to solve the triangle using the Law of Sines:

  PB/sin(C) = CB/sin(P)

  CB = PB·sin(P)/sin(C) = (1200 m)·sin(17°)/sin(30°) ≈ 701.7 m

The speed of the boat is then ...

  x = distance/time = (0.7017 km)/(1/4 h) = 2.8068 km/h

6 0
3 years ago
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