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Gelneren [198K]

2 years ago

8

Solve the system of equations X=11+y 2x+y=19

2 answers:

raketka [301]2 years ago

6 0

Answer:

Step-by-step explanation:

To solve this system of equations, let's first find the value <em>y</em>. We can replace the x in the second equation with 11 + y, since we are told in the <em>first</em> equation that x is equal to 11 + y. So, let's replace x:

2(11 + y) + y = 19

22 + 2y + y = 19

22 + 3y = 19

3y = -3

y = -1

And look at that - we've found our y-value! Now, we can replace the y in the <em>first</em> equation with -1 to find the value of x.

x = 11 + (-1)

x = 10

So, the solution to this system of equations is (10, -1). Hopefully that's helpful!

Furkat [3]2 years ago

3 0

Answer:

x=26/3,y=-7/3

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Listed below are pulse rates (beats per minute) from samples of adult males and females. Does there appear to be a difference

MrMuchimi

Answer:

There appears to be a difference between the pulse rates from samples of adult males and females. The average pulse rate of males is 63.75 while that of females is 75.875.

Coefficient of Variation (male) = 33.44%

Coefficient of variation (female) = 28.35%

Step-by-step explanation:

Mean (male) = $\frac{sum of x}{n} =\frac{1020}{16} =63.75$

Mean (female) = $\frac{sum of y}{n} = \frac{1214}{16} = 75.875$

Standard Deviation (male) = $\sqrt{\frac{sum(x-63.75)^2}{16-1} } =21.315$

Standard Deviation (female) = $\sqrt{\frac{sum(y-75.875)^2}{16-1} } = 21.512$

Coefficient of Variation = $\frac{Std dev}{mean} *100$

For male, CV = $\frac{21.315}{63.75} *100=33.44%$ %

For female, CV = $\frac{21.512}{75.875} *100=28.35$ %

Comparison : Pulse rates of males has more variability than that of females since it has a greater coefficient of variation.

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3 years ago

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Mario is constructing a square dart board. It will consist of a smaller square centered in a larger square. The smaller square m

Ivan

Answer:

6 inches.

Step-by-step explanation:

Let a represent side length of larger square.

We know that area of square is square of its side length, so area of the larger square will be $a^2$ .

The area of smaller square would be $4^2$ .

We will use proportions to solve our given problem.

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$\frac{16}{a^2}=\frac{4}{9}$

Cross multiply:

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