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dolphi86 [110]
3 years ago
10

Triglycerides contain more metabolic energy per unit weight than glycogen because:

Chemistry
1 answer:
klasskru [66]3 years ago
4 0

Answer:

III. Fatty acids are less oxidized than carbohydrates

Explanation:

Both triglycerides and glycogen may be used to obtain energy, this is:

- Triglycerides through the B-oxidation, where a molecule is first activated and entered into mitochondria matrix, to be degraded (oxidized)

- Glycolysis, where a molecule of 6 carbons is splitted in 2 components of 3 carbons each (pyruvate)

As an energy reserve substance, triglycerides have 2 main advantages, compared with glycogen:

1) From the chemical point of view, triglycerides have a more reduced state than glycogen (this is, have more atoms of hydrogens), hence these molecules give twice energy than glycogen

2) As triglycerides are hydrophobic molecules, they remain in an anhydrous form (unlike glycogen, which is hydrophilic), and this makes easier to move these molecules to obtain energy  

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Answer:

gravity that's what I rellat think it is

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What is the name of this compound?<br><br> C6H6-<br> C=O-<br> H
ipn [44]

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8 0
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Read 2 more answers
f the Ksp for HgBr2 is 2.8×10−14, and the mercury ion concentration in solution is 0.085 M, what does the bromide concentration
goldfiish [28.3K]

Answer:

0.057 M

Explanation:

Step 1: Given data

Solubility product constant (Ksp) for HgBr₂: 2.8 × 10⁻⁴

Concentration of mercury (II) ion: 0.085 M

Step 2: Write the reaction for the solution of HgBr₂

HgBr₂(s) ⇄ Hg²⁺(aq) + 2 Br⁻

Step 3: Calculate the bromide concentration needed for a precipitate to occur

The Ksp is:

Ksp = 2.8 × 10⁻⁴ = [Hg²⁺] × [Br⁻]²

[Br⁻] = √(2.8 × 10⁻⁴/0.085) = 0.057 M

7 0
3 years ago
What is meant by polar molecule?
Lostsunrise [7]
A polar molecule<span> has a net dipole as a result of the opposing charges (i.e. having partial positive and partial negative charges) from </span>polar<span> bonds arranged asymmetrically. Water (H</span>2<span>O) is an example of a </span>polar molecule<span> since it has a slight positive charge on one side and a slight negative charge on the other.</span>
3 0
3 years ago
Chemistry, please help! Thanks.
Ilya [14]

Answer:

d. The gold(III) ion is most easily reduced.

Explanation:

The standard reduction potentials are

Au³⁺ + 3e⁻ ⟶ Au;   1.50 V

Hg²⁺ + 2e⁻ ⟶ Hg; 0.85 V

Zn²⁺ + 2e⁻ ⟶ Zn; -0.76 V

Na⁺ + e⁻     ⟶ Na; -2.71 V

A <em>more positive voltage</em> means that there is a <em>stronger driving force</em> for the reaction.

Thus, Au³⁺ is the best acceptor of electrons.

Reduction Is Gain of electrons and, Au³⁺ is gaining electrons,  so

Au³⁺ is most easily reduced.

4 0
3 years ago
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