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Klio2033 [76]
3 years ago
10

Balance sulfur and oxygen​

Chemistry
1 answer:
abruzzese [7]3 years ago
6 0

Answer:

sulphuroxide

because :

S+O2=SO2

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Define Gravitational Potential Energy.
Anna11 [10]

Answer:

Gravitational energy or gravitational potential energy is the potential energy a massive object has in relation to another massive object due to gravity. It is the potential energy associated with the gravitational field, which is released when the objects fall towards each other.

Explanation:

6 0
3 years ago
Consider two flasks at 25 degree Celsius, one contains an ideal gas and the other contains the real gas SO3. Which statement reg
Strike441 [17]

Answer: Option (A) is the correct answer.

Explanation:

In real gases, there exists force of attraction between the molecules at low temperature and high pressure. This is because at low temperature there occurs a decrease in kinetic energy of gas molecules and high pressure causes the molecules to come closer to each other.

As a result, forces of attraction increases as molecules come closer to each other and therefore, gases deviate from an ideal gas behavior.

And, at low pressure and high temperature there exists no force of attraction or repulsion between the molecules of a gas because they have high kinetic energy. Hence, gases behave ideally at these conditions.

Thus, we can conclude that the statement as the temperature approaches 0 K, the volume of the ideal gas will be larger than the volume of SO_{3} because ideal gases lack inter-molecular forces, is true.

3 0
3 years ago
which of these equations is balanced? A. 2Nac1+H2so4--->Na2so4+2Hc1 B. 2cao+H20-->CaC0h)2 C. H20+co-->h2c03 D. MN+FE--&
klemol [59]
The answer will be a because it's balance
5 0
4 years ago
ANSWER ASAP
ArbitrLikvidat [17]

Answer:

c. 3.00 M HCl

Explanation:

From dilution formula

C1V1 = C2V2

C1=?, V1= 10.0ml, C= 1.5, V2= 20.0ml

Substitute and Simplify

C1×10= 1.5×20

C1= 3.00M

5 0
3 years ago
What is the volume, in liters, of 0.500 mol of c3h3 gas at stp?
jarptica [38.1K]
At STP conditions the volume of  1 mol of any ideal gas will be 22.4L

0.500 mol C3H3 x 22.4L / 1 mol = 11.2 L
8 0
3 years ago
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