4NH3+5O2 <=>4NO + 6H2O
Using the definition of Kp, we have
Kp=(Pno^4*Ph2o^6)/(Pnh3^4*Po2^5)
where Pno=partial pressure of NO, etc.
The numerical value for a given temperature can be evaluated when the actual partial pressures are known.
<span>the behavior of the above pair of substances</span> is soluble
Nitrogen can form a diatomic molecule held together by triple bonds.
The heat released by the water when it cools down by a temperature difference AT
is Q = mC,AT
where
m=432 g is the mass of the water
C, = 4.18J/gºC
is the specific heat capacity of water
AT = 71°C -18°C = 530
is the decrease of temperature of the water
Plugging the numbers into the equation, we find
Q = (4329)(4.18J/9°C)(53°C) = 9.57. 104J
and this is the amount of heat released by the water.
