Given:
The x and y axis are tangent to a circle with radius 3 units.
To find:
The standard form of the circle.
Solution:
It is given that the radius of the circle is 3 units and x and y axis are tangent to the circle.
We know that the radius of the circle are perpendicular to the tangent at the point of tangency.
It means center of the circle is 3 units from the y-axis and 3 units from the x-axis. So, the center of the circle is (3,3).
The standard form of a circle is:
![(x-h)^2+(y-k)^2=r^2](https://tex.z-dn.net/?f=%28x-h%29%5E2%2B%28y-k%29%5E2%3Dr%5E2)
Where, (h,k) is the center of the circle and r is the radius of the circle.
Putting
, we get
![(x-3)^2+(y-3)^2=3^2](https://tex.z-dn.net/?f=%28x-3%29%5E2%2B%28y-3%29%5E2%3D3%5E2)
![(x-3)^2+(y-3)^2=9](https://tex.z-dn.net/?f=%28x-3%29%5E2%2B%28y-3%29%5E2%3D9)
Therefore, the standard form of the given circle is
.
Answer:
First one is 5, second one is 6, third one is 6, the last one is 2
Step-by-step explanation:
Hope this helps an mark brainliest please!
Answer:
1
Step-by-step explanation:
By order of operations, we first evaluate the parentheses, which is 2 * 1 = 2. We then evaluate the brackets, which are 3 / 2 =
. Finally,
*
=
or 1.
61 = 3b + 7
3b + 7 = 61
3b = 61 - 7
3b = 54
b = 54/3
b = 18.
Answer: b865e95e
Step-by-step explanation: