Answer:
a=(2/5), b = (-2,6)
Step-by-step explanation:
well slope formula is rise/run. So for the first one you start at the point rise 2 run 5 and you reach the endpoint. That is how you know you got the correct slope. (2/5)
For the second one you start at the first point and you cannot go up because it is a negative slope you run 6 till you hit the other point go down 2. Since you go down 2 that would make it -2. (-2,6)
• The value of the discriminant ,D= -16
,
• The solution to the quadratic equation is
Step - by - Step Explanation
What to find?
• The discriminant d= b² - 4ac
,
• The solution to the quadratic equation.
Given:
5x² - 2x + 1=0
Comparing the given equation with the general form of the quadratic equation ax² + bx + c=0
a=5 b=-2 and c=1
Uisng the quadratic formula to solve;
![x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-b%5Cpm%5Csqrt%5B%5D%7Bb%5E2-4ac%7D%7D%7B2a%7D)
The discriminant D=b² - 4ac
Substitute the values into the discriminant formula and simplify.
D = (-2)² - 4(5)(1)
D = 4 - 20
D = -16
We can now proceed to find the solution of the quadratic equation by substituting into the quadratic formula;
![x=\frac{-(-2)\pm\sqrt[]{-16}}{2(5)}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-%28-2%29%5Cpm%5Csqrt%5B%5D%7B-16%7D%7D%7B2%285%29%7D)
Note that:
√-1 = i
![x=\frac{2\pm\sqrt[]{16\times-1}}{10}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B2%5Cpm%5Csqrt%5B%5D%7B16%5Ctimes-1%7D%7D%7B10%7D)
![x=\frac{2\pm\sqrt[]{16}\times\sqrt[]{-1}}{10}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B2%5Cpm%5Csqrt%5B%5D%7B16%7D%5Ctimes%5Csqrt%5B%5D%7B-1%7D%7D%7B10%7D)
That is;
Answer:
19°
Step-by-step explanation:
Set up the equation (triangles add up to 180 degrees)(Right angles are 90 degrees).
39 + 90 + 2x + 13 = 180
142 + 2x = 180
2x = 38
x = 19
So,
Home ---- gym = 3.6 mi.
gym ---- store = .7 mi.
store ----- home = x
3.6 + .7 + x = 7.2 mi.
Collect Like Terms
4.3 + x = 7.2
Subtract 4.3 from both sides
x = 2.9
The distance from the store to her home is 2.9 miles.
Step-by-step explanation:
Use SOH-CAH-TOA.
Sine = Opposite / Hypotenuse
Cosine = Adjacent / Hypotenuse
Tangent = Opposite / Adjacent
Let's start with #12. The hypotenuse is 18. The side adjacent to ∠B is 6. Since we have the adjacent side and hypotenuse, we should use cosine.
cos B = 6/18
Solving for B:
B = cos⁻¹(6/18)
Using a calculator:
B ≈ 70.5°
Now let's do #14. The side adjacent to ∠B is 19, and the side opposite of ∠B is 22. Since we have the adjacent side and opposite side, we should use tangent.
tan B = 22/19
Solving for B:
B = tan⁻¹(22/19)
Using a calculator:
B ≈ 49.2°
