
Scientific notation for above value is ~
Answer:
Area = Length × width
16 = (3x +2 ) × ( x)
16 = 3x² +2x
3x² +2x -16=0
( 3x+8 ) ( x -2 ) =0
3x +8=0 —> 3x = – 8 —> x = – 8/3 —> x = – 2.6
x-2=0 —> x = 2
I hope I helped you^_^
Answer:
wait what is your math problem?
Step-by-step explanation:
Answer:
The rocket would be in the air for 8.125 seconds after launch.
Step-by-step explanation:
Given that the height of the rocket, h = 260t - 16
.
To determine how long the rocket would be in the air, differentiate h totally with respect to t.
So that, total derivative of h is given as;
= 
0 = 260 - 16 x 2t
= 260 - 32t
0 = 260 - 32t
32t = 260
t = 
= 8.125
t= 8.125 seconds
The rocket would be in the air for 8.125 seconds after launch.