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Stels [109]
4 years ago
9

Classify triangle BCD based on side lengths, given:

Mathematics
2 answers:
Pavel [41]4 years ago
8 0

AB = BE = 5

BD = BE + ED = 5 + 3 = 8

BC = 8

BD = BC

CD = 5 which is not equal to 8.

Triangle BCD has exactly 2 congruent sides.

Answer: Triangle BCD is isosceles.

aev [14]4 years ago
3 0

BCD is an isosceles triangle

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The decimal i am thinking of is 3 hundredths less than 3 tenths. What is my decimal
Alinara [238K]

3 hundredths - 3/100

3 tenths - 3/10

3/10 is the same as 30/100

3/100 less than 30/100 is 30/100-3/100 = 27/100

Answer: 27/100

6 0
3 years ago
Evaluate the expression for f = –19.8.
DiKsa [7]

Answer:

-2

Step-by-step explanation:

17.8 + f =

17.8 + (-19.8)

= -2

7 0
3 years ago
How much carpet does Jordan need to cover the surface of the post including the bottom
Artist 52 [7]

Answer:

It would be 3,800

Step-by-step explanation:

You have to find the surface area of the post

( ( 90 x 10 ) x 4 ) + ( 10 x 10 ) x 2 ) = 3,800

        3,600 +  200  = 3,800

Hope this helps

7 0
3 years ago
Justify why a/b x b/c x c/d x d/ e is equal to a/e when b,c,d, and e are not zero?
san4es73 [151]
\frac { a }{ b } \times \frac { b }{ c } \times \frac { c }{ d } \times \frac { d }{ e } \\ \\ =\frac { a\cdot b\cdot c\cdot d }{ b\cdot c\cdot d\cdot e } \\ \\ =\frac { a }{ e } \cdot \frac { b\cdot c\cdot d }{ b\cdot c\cdot d } \\ \\ =\frac { a }{ e } \cdot 1\\ \\ =\frac { a }{ e }
6 0
4 years ago
A quadratic relation has zeros at 3 and –5. The parabola goes through the point (2, –14). What is the equation of the parabola i
olasank [31]

Answer:

\displaystyle  2 {x}^{2}  + 4x - 30 = 0

Step-by-step explanation:

we are given the zeros and a point where it goes through of a quadratic equation

remember that when the roots are given then the function should be

\displaystyle \: y =  a(x -  x_{1})(x -  x_{2})

where a is the leading coefficient and x1 and x2 are the roots

substitute:

\displaystyle y = a(x -  (3))(x -  ( - 5))

simplify:

\displaystyle y = a(x -  3)(x  + 5)

now the given point tells us that when x is 2 y is -14 therefore by using the point we can figure out a

substitute:

\displaystyle a(2 -  3)(2  + 5)  =  - 14

simplify parentheses:

\displaystyle a(  - 1)(7)  =  - 14

simplify multiplication:

\displaystyle  - 7a =  - 14

divide both sides by -7:

\displaystyle  a =  2

altogether substitute:

\displaystyle y = 2(x -  3)(x  + 5)

since it want the equation y should be

\displaystyle  2(x -  3)(x  + 5)  = 0

recall quadratic equation standard form:

\displaystyle   {ax}^{2}  + bx + c = 0

so simplify parentheses:

\displaystyle  2( {x}^{2}  + 2x - 15 )  = 0

distribute:

\displaystyle  2 {x}^{2}  + 4x - 30 = 0

hence,

the equation of the parabola in standard form is <u>2</u><u>x</u><u>²</u><u>+</u><u>4</u><u>x</u><u>-</u><u>3</u><u>0</u><u>=</u><u>0</u>

8 0
3 years ago
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