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2 years ago

Please help me with this please and thank you

Mathematics

1 answer:

Bond [772]2 years ago

5 0

I can’t see the problem very well, but your answer should be the one with (-3/2,0) as the intersecting point on the graph.

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Read 2 more answers

Prove that a triangle with the sides a - 1 cm to root under a

vivado [14]

Question is Incomplete, Complete question is given below.

Prove that a triangle with the sides (a − 1) cm, 2√a cm and (a + 1) cm is a right angled triangle.

Answer:

∆ABC is right angled triangle with right angle at B.

Step-by-step explanation:

Given : Triangle having sides (a - 1) cm, 2√a and (a + 1) cm.

We need to prove that triangle is the right angled triangle.

Let the triangle be denoted by Δ ABC with side as;

AB = (a - 1) cm

BC = (2√ a) cm

CA = (a + 1) cm

Hence,

${AB}^2 = (a -1)^2$

Now We know that

$(a- b)^2 = a^2+b^2 - 2ab$

So;

${AB}^2= a^2 + 1^2 -2\times a \times1$

${AB}^2 = a^2 + 1 -2a$

Now;

${BC}^2 = (2\sqrt{a})^2= 4a$

Also;

${CA}^2 = (a + 1)^2$

Now We know that

$(a+ b)^2 = a^2+b^2 + 2ab$

${CA}^2= a^2 + 1^2 +2\times a \times1$

${CA}^2 = a^2 + 1 +2a$

${CA}^2 = AB^2 + BC^2$

[By Pythagoras theorem]

$a^2 + 1 +2a = a^2 + 1 - 2a + 4a\\\\a^2 + 1 +2a= a^2 + 1 +2a$

Hence, ${CA}^2 = AB^2 + BC^2$

Now In right angled triangle the sum of square of two sides of triangle is equal to square of the third side.

This proves that ∆ABC is right angled triangle with right angle at B.

4 0

3 years ago

ron wants to build a ramp with a length of 14 ft and an angle of elevation of 26° the height of the ramp is about 6.1 ft. what i

Bezzdna [24]

Answer:

12.58 feet.

Step-by-step explanation:

Ron wants to build a 14 ft. ramp with an angle of the rise of 26° and the height of the ramp is about 6.1 ft.

We have to find out the length of the base of the ramp.

Now, the ramp forms a right triangle with the base and the height and here, the hypotenuse of the triangle is the ramp itself i.e. 14 ft.

If the base length is x feet, then we can write using the trigonometry

$\cos 26^{\circ} = \frac{\textrm{Base}}{\textrm {Hypotenuse}} = \frac{x}{14}$

⇒ x = 14 cos 26° = 12.58 feet. (Answer)

4 0

3 years ago