The a point is refrected through the line y = x, the new point is found by interchanging the x and y-cordinate of the original point. i.e. if the original point is (a, b) and is refrected through the line y = x, the new point will be (b, a).
48 goes in to 2,652 how many times...that your answer...48 cannot go into 2 6 or 5 but it can into 265 5 times which equal240 subtract that from265 =25 ,48 cannot go in to 25 so bring down the 2 to make it 252 then divide 48 by 252 which goes 5 times equaling12 48 cannot go in to 12 so add a 0 to 2652 to make it 26520 then bring the 0 down to make 12 120 then divide 48 into that which it goes 2 times equaling 96 120subtract 96=24 48 cannot go into 24 so add another 0 to 26520 to make it 265200 bring down the zero to make 24 into 240 divide 48 into that which gives you240 subtract 240 from 240 = 0 so your answer is 48 divide into 2652=525
Answer:
40 degrees
Step-by-step explanation:
The sum of the angles is 180.
A 100 degree angle cannot be a base angle because then
the sum of the base angles would be 200 degrees.
The 100 must be the vertex angle.
Equation:
x + x + 100 = 180
2x = 80
x = 40 degrees.
Each of the base angles is 40 degrees.
Answer:
V(max) = 8712.07 in³
Dimensions:
x (side of the square base) = 16.33 in
girth = 65.32 in
height = 32.67 in
Step-by-step explanation:
Let
x = side of the square base
h = the height of the postal
Then according to problem statement we have:
girth = 4*x (perimeter of the base)
and
4* x + h = 98 (at the most) so h = 98 - 4x (1)
Then
V = x²*h
V = x²* ( 98 - 4x)
V(x) = 98*x² - 4x³
Taking dervatives (both menbers of the equation we have:
V´(x) = 196 x - 12 x² ⇒ V´(x) = 0
196x - 12x² = 0 first root of the equation x = 0
Then 196 -12x = 0 12x = 196 x = 196/12
x = 16,33 in ⇒ girth = 4 * (16.33) ⇒ girth = 65.32 in
and from equation (1)
y = 98 - 4x ⇒ y = 98 -4 (16,33)
y = 32.67 in
and maximun volume of a carton V is
V(max) = (16,33)²* 32,67
V(max) = 8712.07 in³
Answer:
Step-by-step explanation:
Factor the equation 
using formula for difference of the cubes:
then
1. The equation 
has real solution 
2. The equation 
has negative discriminant 
then it has two complex solutions
