Question

Solve the system. find x,y, and z please show all steps x-y+z=1 x+y+3z=-3 2x-y+2z=0

Answer 1

Solving the system we get, x= -1, y= -2 and z= 0

Step-by-step explanation:

Solving the equations to find x, y and z

$x-y+z=1\,\,\,eq(1)\\x+y+3z=-3\,\,\,eq(2)\\2x-y+2z=0\,\,\,eq(3)$

Adding eq(1) and eq(2)

$x-y+z=1\\x+y+3z=-3\\--------\\2x+4z=-2\,\,\,\,eq(4)$

Adding eq(2) and eq(3)

$x+y+3z=-3\\2x-y+2z=0\\----------\\3x+5z=-3\,\,\,eq(5)$

Multiplying eq(4) by 3 and eq(5) by 2

$6x+12z=-6\\6x+10z=-6\\-\,\,\,-\,\,\,\,\,\,\,\,\,\,\,\,\,\,+\\----------\\2z=0\\z=0$

So, value of z =0

Putting value of z in eq(4)

$2x+4z=-2\\2x+4(0)=-2\\2x=-2\\x=-1$

So, value of x = -1

Now putting value of z=0 and x =-1 in equation 1

$x-y+z=1\\-1-y+0=1\\-y=1+1\\-y=2\\y=-2$

So, value of y = -2

So, solving the system we get, x= -1, y= -2 and z= 0

Keywords: Solve the system

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