Given the graph y = f(x)
The graph y = f(cx), where c is a constant is refered to as horizontal stretch/compression
A horizontal stretching is the stretching of the graph away from the y-axis.
A horizontal compression is the squeezing of the graph towards the
y-axis. A compression is a stretch by a factor less than 1.
If | c | < 1 (a fraction between 0 and 1), then the graph is stretched horizontally by a factor of c units.
If | c | > 1, then the graph is compressed horizontally by a factor of c units.
For values of c that are negative, then the horizontal
compression or horizontal stretching of the graph is followed by a
reflection across the y-axis.
The graph y = cf(x), where c is a constant is referred to as a
vertical stretching/compression.
A vertical streching is the stretching of the graph away from the x-axis. A vertical compression is the squeezing of the graph towards the x-axis. A compression is a stretch by a factor less than 1.
If | c | < 1 (a fraction between 0 and 1), then the graph is compressed vertically by a factor of c units.
If | c | > 1, then the graph is stretched vertically by a factor of c units.
For values of c that are negative, then the vertical compression or vertical stretching of the graph is followed by a reflection across the x-axis.
what is the best and easiest method to use to find sides A and B?
B
Tables are created by substitute a set of input values into the function to create outputs. The required table is as shown below
<em>x | y</em>
<em>0 -3 </em>
<em>1 -2.5</em>
<em>2 -2 </em>
<h3>Tables and values</h3>
Tables are created by substitute a set of input values into the function to create outputs
Using x = 0, 1 and 2 as the input values
Given the function
y = 1/2x - 3
If x = 0
y = 1/2(0) - 3
y = -3
If x = 1
y = 1/2(1) - 3
y = -2.5
If x = 2
y = 1/2(2) - 3
y = -2
Hence the required table is as shown below
x | y
0 -3
1 -2.5
2 -2
Learn more on tables and values here: brainly.com/question/12151322
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Answer:
a=15
Step-by-step explanation:
By pythagoras' theorem
25²=20²+a²
625=400+a² group like terms
a²=625-400
a²=225
therefore a=15
