Question

A cylindrical container's lateral surface is to be covered by a label. The container's diameter is 5 inches, and its height is 8 inches.
How much paper is needed to create the label?

A. 39.3 in^2
B. 82.5 in^2
C. 126 in^2
D. 165 in^2

Answer 1

Given is :

The lateral area of a cylinder is to be covered by a label.

The lateral surface area of a cylinder is calculated by the following formula:

$2\pi rh$

Here r = radius and h= height of the cylinder

Now diameter = 5 inches.

So, radius = $\frac{5}{2}=2.5$

Height = 8 inches

Hence, surface area = $2*3.14*2.5*8=125.66$ or can be rounder off to 126 square inches. So, this much paper is needed.

Hence, option C = 126 square inches is the answer.

Answer 2

Answer:

The correct option is C. 126 in²

Step-by-step explanation:

Diameter of the container = 5 inches

⇒ radius of the container = 2.5 inches

Height of the container = 8 inches

To find how much paper is needed to create the label : We need to find the lateral surface area of the cylindrical shaped container

Lateral Surface Area of Cylinder = 2·π × radius × height

                                                      = 2 × 3.14 × 2.5 × 8

                                                      = 125.66 square inches

                                                      ≈ 126 square inches

Hence, 126 square inches of paper is needed to create the label.

So, The correct option is C. 126 in²