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3 years ago

Write 4.9 × 10–8 in decimal notation

Mathematics

1 answer:

34kurt3 years ago

7 0

Answer:

0.000000049.

Step-by-step explanation:

This will have 7 zeros after the decimal point followed by 49:

4.9 × 10^–8 = 0.000000049.

If we imagine the decimal point making jumps to the right over the digits it takes 8 jumps till it gets to 4.9. that's where the -8 comes in.

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10.

yan [13]

Answer:

D. y = -5^x – 27

Step-by-step explanation:

Find the negative reciprocal of the slope of the original line and use the point-slope formula y − y 1 = m ( x − x 1 ) to find the line perpendicular to − x + 5 y = 14 .

y = − 5 x − 27 PERPENDICULAAR

...................................................................................................................................................

Find the slope of the original line and use the point-slope formula y − y 1 = m ( x − x 1 ) to find the line parallel to − x + 5 y = 14 .

y = 1 /5 x − 1 PARALLEL

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3 years ago

You find out that you get a 20% off on your favorite sweater, and you also get an additional 30% off. Does the store apply the d

Marta_Voda [28]

Answer:

Apply them sequentially.

Step-by-step explanation:

The store would apply the discounts sequentially because it gives less of a discount compared to if they did it all at once.

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3 years ago

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???????????????? Help it's probably super easy btw

Deffense [45]

Points:

Quadrant I: (+, +)
Quadrant II: (-, +)
Quadrant III: (-, -)
Quadrant IV: (+, -)

Thus the point (5,4) is found in Quadrant I.

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3 years ago

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Find all values of the angle θ (in radians, with 0 ≤ θ < 2π) for which the matrix a = cos θ −sin θ sin θ cos θ has real eigen

harina [27]

The matrix

$A=\begin{bmatrix}\cos\theta&-\sin\theta\\\sin\theta&\cos\theta\end{bmatrix}$

has eigenvalues $\lambda$ such that

$\det(A-\lambda I)=\begin{vmatrix}\cos\theta-\lambda&-\sin\theta\\\sin\theta&\cos\theta-\lambda\end{vmatrix}=0$

$(\cos\theta-\lambda)^2+\sin^2\theta=0$

$(\cos\theta-\lambda)^2=-\sin^2\theta$

$\cos\theta-\lambda=\pm\sqrt{-\sin^2\theta}$

$\lambda=\cos\theta\pm\sqrt{-\sin^2\theta}$

$\sin^2\theta\ge0$ for all values of $\theta$ , so we need to have $\sin\theta=0$ in order for $\lambda$ to be real-valued. This happens for

$\sin\theta=0\implies\theta=n\pi$

where $n$ is any integer, and over the given interval we have $\theta=0$ and $\theta=\pi$ .

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3 years ago

Consider the system of equations. 3x + 2y = 16, x + y = 4 Which numerical values could you multiply the second equation by to el

andrezito [222]

Answer: -2

Step-by-step explanation:

3x+2y=16

x+y=4 multiply by -2

-2x-2y=-8

3x+2y=16 ------a

-2x-2y=-8 -------b

Add equation a and b

(3x+-2x)+(2y+-2y) = 16+(-8)

x+0=8 (y has been eliminated)

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