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3 years ago

How does knowing the difference between the gain and the loss tell you the overall result?

2 answers:

7 0

Unlike gains, there are is no outflow of money for taking a loss; it simply means that the sale of an asset wasn't greater than the original cost.

I found this very interesting!

kipiarov [429]3 years ago

3 0

Answer:

Losses are similar to gains in that both are recognized on the income statement only when an asset is sold and a loss is taken. ... Unlike gains, there is no outflow of money for taking a loss; it simply means that the sale of an asset wasn't greater than the original cost. (got the answer from google hehe)

Step-by-step explanation:

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For the following problem state the objective function and the constraints. DO NOT solve:

Mama L [17]

Answer:

If we define S as the number Sprinkle's umbrellas, and H as the Hurricane's umbrellas, the profit P can be expressed as:

$P=3S+5H$

The restriction for cloth can be written as:

$S+2H\leq500$

The restriction for metal can be written as:

$2S+3H\leq600$

The restriction for wood can be written as:

$4S+7H\leq800$

The condition for S and H to be positive is:

$S, H \geq0$

Step-by-step explanation:

We have an objective function that, in this case, we want ot maximize.

This function is the Profit (P).

If we define S as the number Sprinkle's umbrellas, and H as the Hurricane's umbrellas, the profit can be expressed as:

$P=3S+5H$

We have 3 restrictions, plus the condition that both S and H are positive.

The restriction for cloth can be written as:

$S+2H\leq500$

The restriction for metal can be written as:

$2S+3H\leq600$

The restriction for wood can be written as:

$4S+7H\leq800$

The condition for S and H to be positive is:

$S, H \geq0$

5 0

3 years ago

Finding an Equation of a tangent Line in Exercise, find an equation of the tangent line to the graph of the function at the give

frutty [35]

Answer:

$y=\dfrac{3x}{e}+\dfrac{4}{e}$

this is the equation of the tangent at point (-1,1/e)

Step-by-step explanation:

to find the tangent line we need to find the derivative of the function g(x).

$g(x) =e^{x^3}$

we know that $\frac{d}{dx}(e^{f(x)})=e^{f(x)}f'(x)$

$g'(x) =e^{x^{3}}(3 x^{2})$

$g'(x) =3 x^{2} e^{x^{3}}$

this the equation of the slope of the curve at any point x and it also the slope of the tangent at any point x. hence, g'(x) can be denoted as 'm'

to find the slope at (-1,1/e) we'll use the x-coordinate of the point i.e. x = -1

$m =3 (-1)^{2} e^{(-1)^{3}}\\m =3e^{-1}\\m=\dfrac{3}{e}$