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White raven [17]

3 years ago

6

juan weight 18 pounds more than marie, using w to represent weight , write an expression for marie and juan's weight, write an e

xpression for marie and juan's weight

1 answer:

fgiga [73]3 years ago

5 0

W-18 is the answer hope it helps

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cestrela7 [59]

Answer:

9/4

Step-by-step explanation:

2(x - 10) + 4 = -6x + 2

2x - 20 + 4 = -6x + 2

2x - 16 = -6x + 2

8x - 16 = 2

8x = 18

x = 18/8 or 9/4

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bazaltina [42]

Answer:

10ibs=1000% 6ibs=600%

Step-by-step explanation:

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30+ Points!!!<br> 5. Solve the following inequalities.<br> a) 2 log3x – 2 logx3 -3 <0

Ilya [14]

Answer:

I answered your last question also

2 log3x – 2 logx3 -3 <0

$\mathrm{Subtract\:}2\log ^3\left(x\right)\mathrm{\:from\:both\:sides}$

$2\log ^3\left(x\right)-2logx^3-3-2\log ^3\left(x\right)$

$\mathrm{Simplify}$

$-2logx^3-3$

$\mathrm{Add\:}3\mathrm{\:to\:both\:sides}$

$-2logx^3-3+3$

$\mathrm{Simplify}$

$-2logx^3$

$Multiply\:both\:sides\:by\:-1\:\left(reverse\:the\:inequality\right)$

$\left(-2logx^3\right)\left(-1\right)>-2\log ^3\left(x\right)\left(-1\right)+3\left(-1\right)$

$\mathrm{Simplify}$

$2lx^3og>2\log ^3\left(x\right)-3$

$\mathrm{Divide\:both\:sides\:by\:}2lx^3o;\quad \:l>0$

$\frac{2lx^3og}{2lx^3o}>\frac{2\log ^3\left(x\right)}{2lx^3o}-\frac{3}{2lx^3o};\quad \:l>0\\$

$\mathrm{Simplify}$

$g>\frac{2\log ^3\left(x\right)-3}{2lx^3o};\quad \:l>0$

Step-by-step explanation:

6 0

2 years ago