Move
100 to the left of a.
which makes 100a,month
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find y=mx+b for line parallel to AB.
The line that is parallel will have the same slope as line AB:
the slope of line AB is
m=(8-3)/(-10-2)
=5/-12
=-5/12
Since the line going through X is parallel the vertical distance of the new line to AB is the same for all values of the domain(x-axis).
at x=-5 the point X has the y value of 10 which is 4 more than the y value for AB based on the graph.
To find the intercept b of the line going through X that is parallel to AB we just add 4 to the intercept of AB, which is 4 so
4+4=8
Answer:
1 :
Step 2 :
Equations which are never true :
2.1 Solve : 2 = 0
This equation has no solution.
A a non-zero constant never equals zero.
Solving a Single Variable Equation :
2.2 Solve : 2x+1 = 0
Subtract 1 from both sides of the equation :
2x = -1
Divide both sides of the equation by 2:
x = -1/2 = -0.500
One solution was found :
x = -1/2 = -0.500
The answer should be 315.95
(x^2-5)(3x-1)
Here's how I got this answer:
I found the GCF for each part of the polynomial.
3x^3 and -15x both contain 3x, and -x^2 and 5 share -1.
I then can divide the polynomial by 3x-1, and I get x^2-5
(Okay, that's not what I really did, but I can solve these on sight and don't remember the proper way to do it.)
