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3 years ago

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The nile river is 6690 kilometers long.This is 394 kilometers longer than the Amazon River.How long is the Amazon River?

2 answers:

valentinak56 [21]3 years ago

6 0

Answer:

The nile river is 6690 kilometers long.This is 394 kilometers longer than the Amazon River.How long is the Amazon River?

6690-394=6296 kilometers

Step-by-step explanation:

Advocard [28]3 years ago

3 0

Answer:

The Amazon river is 6296 kilometers long.

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Answer:

Answer:

P(t) = 10t - 400

Step-by-step explanation:

Selling price of each ticket = $10

Cost of setting up the dance= $400

Profit = Revenue - cost

Revenue = price × quantity

Revenue that will maximize profit = 10t

where t= quantity of tickets that maximises profits

Cost = $400

Profit(t) = Revenue - cost

P(t)= 10t - 400

Step-by-step explanation:

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3 years ago

Mae Ling earns a weekly salary of $395 plus a 5.0% commission on sales at a gift shop. How much would she make in a work week if

Alenkinab [10]

Answer:

Calculate 5% of what she sold. Then add it to her weekly salary

5% =0.05

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3 years ago

6.34 1.645<br> 10.3401-0.34<br> 45

Nostrana [21]

Step-by-step explanation:

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8 0

3 years ago

If p-1/p=2, find the value of p^3+1/p^3. Help me fast.

tekilochka [14]

Answer:

$\\\\\frac{P^3 \ + \ 1}{P^3} = 0$

Step-by-step explanation:

Given;

$\frac{P-1 }{P} = 2\\\\From \ the \ equation \ above \ we \ determine \ the \ value \ of \ p \ as \ follows;\\\\P-1 = 2P\\\\P-2P = 1\\\\-P = 1\\\\P = -1$

$Now\ solving \ the \ given \ question;\\\\\frac{P^3 \ + \ 1}{P^3} \\\\Substitute \ the \ value \ of \ "P" \ into \ the \ equation;\\\\\frac{P^3 \ + \ 1}{P^3} = \frac{(-1)^3 \ + \ 1}{(-1)^3} = \frac{-1 \ + \ 1}{-1} = \frac{0}{-1} = 0$

4 0

3 years ago

1) Determine the discriminant of the 2nd degree equation below:

Aleksandr-060686 [28]

$\LARGE{ \boxed{ \mathbb{ \color{purple}{SOLUTION:}}}}$

We have, Discriminant formula for finding roots:

$\large{ \boxed{ \rm{x = \frac{ - b \pm \: \sqrt{ {b}^{2} - 4ac} }{2a} }}}$

Here,

x is the root of the equation.
a is the coefficient of x^2
b is the coefficient of x
c is the constant term

1) Given,

3x^2 - 2x - 1

Finding the discriminant,

➝ D = b^2 - 4ac

➝ D = (-2)^2 - 4 × 3 × (-1)

➝ D = 4 - (-12)

➝ D = 4 + 12

➝ D = 16

2) Solving by using Bhaskar formula,

❒ p(x) = x^2 + 5x + 6 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 5\pm \sqrt{( - 5) {}^{2} - 4 \times 1 \times 6 }} {2 \times 1}}}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 5 \pm \sqrt{25 - 24} }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 5 \pm 1}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = - 2 \: or - 3}}}$

❒ p(x) = x^2 + 2x + 1 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 2 \pm \sqrt{ {2}^{2} - 4 \times 1 \times 1} }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 2 \pm \sqrt{4 - 4} }{2} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 2 \pm 0}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = - 1 \: or \: - 1}}}$

❒ p(x) = x^2 - x - 20 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - ( - 1) \pm \sqrt{( - 1) {}^{2} - 4 \times 1 \times ( - 20) } }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ 1 \pm \sqrt{1 + 80} }{2} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{1 \pm 9}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = 5 \: or \: - 4}}}$

❒ p(x) = x^2 - 3x - 4 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - ( - 3) \pm \sqrt{( - 3) {}^{2} - 4 \times 1 \times ( - 4) } }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{3 \pm \sqrt{9 + 16} }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{3 \pm 5}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = 4 \: or \: - 1}}}$

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5 0

3 years ago

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