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3 years ago

7

Point M is located at (3,7). If point M is translated 2 units to the left and 4 units down, what are the coordinates of M Q1 (-1

,5) Q2 (1,3) Q3 (5,3) Q4 (7,5)

2 answers:

Natasha_Volkova [10]3 years ago

3 0

The answer is simply (1,3) just subtract 2 from 3 and 4 from 7.

olga_2 [115]3 years ago

3 0

I believe the answer should be Q1 (1,3). You can not have a negative number in Q1. Please check your question again to make certain you wrote it correctly.

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The area of a trapezoid is 1400 cm and the bases measure 20 cm and 50 cm, find the height.

arlik [135]

Using the formulaA=a+b2hSolving forhh=2Aa+b=2·1400 20+50=40cm

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3 years ago

I need help solving this

Stolb23 [73]

Step-by-step explanation:

So in the equation given, y = 2x - 3

you substitute x for whats given in the table in the x column.

Example

In the graph the first number under the x colum is -1.

y = 2x - 3 in the equation you take out x and put -1.

So now the equation becomes y = 2 × -1 - 3.

Using bedmas to solve the question you should get -5

Which now means y = -5

To plot the point now x would be -1 and y would be -5 (-1, -5)

Same thing for the second number in the x Column.

y = 2 × 1 - 3 which equals -1

To plot it

x = 1 y = -1. (1, -1)

And for the last number 3.

Agai. You substitute x for 3 which makes the equation y = 2 × 3 - 3

this gives you 3 and to plot it

x would be 3 and y would be 3

4 0

3 years ago

Please could you find the answers to the questions in the attachment.

Fudgin [204]

( $\frac{x1+x2}{2} , \frac{y1+y2}{2}$ )we need 3 equations
1. midpoint equation which is ( $\frac{x1+x2}{2} , \frac{y1+y2}{2}$ ) when you have 2 points

2. distance formula which is D= $\sqrt{(x2-x1)^{2}+(y2-y1)^{2}}$

3. area of trapezoid formula whhic is (b1+b2) times 1/2 times height

so

x is midpoint of B and C
B=11,10
c=19,6
x1=11
y1=10
x2=19
y2=6
midpoint=( $\frac{11+19}{2} , \frac{10+6}{2}$ )
midpoint=( $\frac{30}{2} , \frac{16}{2}$ )
midpoint= (15,8)

point x=(15,8)

y is midpoint of A and D
A=5,8
D=21,0
x1=5
y1=8
x2=21
y2=0
midpoint=( $\frac{5+21}{2} , \frac{8+0}{2}$ )
midpoint=( $\frac{26}{2} , \frac{8}{2}$ )
midpoint=(13,4)

Y=(13,4)

legnths of BC and XY
B=(11,10)
C=(19,6)
x1=11
y1=10
x2=19
y2=6
D= $\sqrt{(19-11)^{2}+(6-10)^{2}}$
D= $\sqrt{(8)^{2}+(-4)^{2}}$
D= $\sqrt{64+16}$
D= $\sqrt{80}$
D= $4 \sqrt{5}$
BC= $4 \sqrt{5}$

X=15,8
Y=(13,4)
x1=15
y1=8
x2=13
y2=4
D= $\sqrt{(13-15)^{2}+(4-8)^{2}}$
D= $\sqrt{(-2)^{2}+(-4)^{2}}$
D= $\sqrt{4+16}$
D= $\sqrt{20}$
D= $2 \sqrt{5}$
XY= $2 \sqrt{5}$

the thingummy is a trapezoid
we need to find AD and BC and XY
we already know that BC= $4 \sqrt{5}$ and XY= $2 \sqrt{5}$

AD distance
A=5,8
D=21,0
x1=5
y1=8
x2=21
y2=0
D= $\sqrt{(21-5)^{2}+(0-8)^{2}}$
D= $\sqrt{(16)^{2}+(-8)^{2}}$
D= $\sqrt{256+64}$
D= $\sqrt{320}$
D= $4 \sqrt{2}$
AD= $4 \sqrt{2}$

so we have
AD= $4 \sqrt{2}$
BC= $4 \sqrt{5}$
XY= $2 \sqrt{5}$

AD and BC are base1 and base 2
XY=height
so
(b1+b2) times 1/2 times height
( $4 \sqrt{2}+4 \sqrt{5}$ ) times 1/2 times $2 \sqrt{5}$ =
( $4 \sqrt{2}+4 \sqrt{5}$ ) times \sqrt{5} [/tex] =
$4 \sqrt{10}+4*5$ = $4 \sqrt{10}+20$ =80 $\sqrt{10}$ =252.982

X=(15,8)
Y=(13,4)
BC= $4 \sqrt{5}$
XY= $2 \sqrt{5}$
Area=80 $\sqrt{10}$ square unit or 252.982 square units

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3 years ago

Three bags of rice weigh 90 kgs. How much do 9 bags weigh?

Varvara68 [4.7K]

9 bags would weigh 270kgs

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2 years ago

Read 2 more answers

Juan wishes to build a garden at the bottom of his property. He wants to split it in two, like the diagram below, so he can plan

SCORPION-xisa [38]

Answer:

20 ft by 60 ft

Step-by-step explanation:

"What should the dimensions of the garden be to maximize this area?"

If y is the length of the garden, parallel to the stream, and x is the width of the garden, then the amount of fencing is:

120 = 3x + y

And the area is:

A = xy

Use substitution:

A = x (120 − 3x)

A = -3x² + 120x

This is a downward facing parabola. The maximum is at the vertex, which we can find using x = -b/(2a).

x = -120 / (2 · -3)

x = 20

When x = 20, y = 60. So the garden should be 20 ft by 60 ft.

4 0

3 years ago