All categories

3 years ago

Estimate the quotients using compatibale numbers. 8631÷10

1 answer:

7 0

Well what you would have to do is look for numbers that are easy to divide. For example, lets try 9000/10, and so the answer would be 900 and so if you divide the actually numbers, you could compare them, and see if 900 would be a reasonable.

You might be interested in

2x+3=5 and 3y+7=6, what is x+y?

WITCHER [35]

Answer:

x=1 y=14 they both equal 15

Step-by-step explanation:

!!$$

7 0

3 years ago

Read 2 more answers

Helpppp plssssss I need to get my grade up in math

KatRina [158]

Answer: 1.25 square feet

This converts to the improper fraction 5/4

===========================================================

Explanation:

The area of the triangle on the left is base*height/2 = 0.5*2/2 = 0.5 square feet. Note that 1/2 = 0.5

The area of the triangle on the right side is base*height/2 = 0.2*3/2 = 0.75 square feet. This converts to the fraction 3/4

Add up the two results: 0.5+0.75 = 1.25 square feet

-----------

If you need the answer as an improper fraction, then,

1.25 = 1 + 0.25

1.25 = 1 + 1/4

1.25 = 4/4 + 1/4

1.25 = (4+1)/4

1.25 = 5/4

3 0

3 years ago

Find the sum which amounts to Rs 9261 at 10% per annum compound interest for 18 months ,interest payable half yearly

AleksAgata [21]

Find the sum which amounts to Rs 9261 at 10% per annum compound interest for 18 months ,interest payable half yearly

$A=P(1+\frac{r}{n})^{nt}$ , where A is amount , r is rate =10% = 0.10 , n is intervals of compounding n=2 , t is time = 18 months=1.5 years

Lets plug in

$9261=P(1+\frac{0.10}{2})^{2*1.5}$

$9261 = P(1.002)^{3}$

$9261 = P(1.006012008)$

divide both sides by 1.006012008

$P= Rs 9205.6555$

6 0

3 years ago

Simply the problem.

Marat540 [252]

Answer:

Step-by-step explanation:

$\sqrt{3}\cdot\sqrt{21}= \\\\\sqrt{3\cdot 21}= \\\\\sqrt{63}= \\\\3\sqrt{7}$

Therefore, the correct answer is choice C. Hope this helps!

6 0

4 years ago

Read 2 more answers

Use always, sometimes or never to make a true statement:

viva [34]

Answer:

1. Intersecting lines are always coplanar

2. Two planes never intersect in exactly one point

3. Three points are always coplanar

4. A plane containing two points of a line always contains the entire line

5. Four points are sometimes coplanar

6. Two lines never meet in more than one point.

7. Two skew lines are never coplanar

8. Line TQ and Line QT are always the same line.

Step-by-step explanation:

Note: Coplanar means "In the same plane"

1. Each line exist in many planes. But different lines must share at least one plane for them to intersect. That is why intersecting lines are always coplanar.

2. Two planes never intersect at exactly one point because only lines intersect at a point. Planes can only intersect along a line.

3.Three points are always coplanar because in geometry, a group of points are coplanar because there is a geometric plane that they all lie on.

4. A plane containing two points of a line always contains the entire line. Yes

5. Four points are only sometimes coplanar because there is a probability that they may all not lie on the same plane

6. Two lines never meet in more than one point because lines are basically straight and cannot bend over to intersect at another point

7. Two skew lines are never coplanar because skews lines are lines that do not intersect and are never parallel.

8. Line TQ and Line QT are always the same line because a line is straight and extends from one point to the other. So, if a line is labelled TQ calling it QT means the same thing

4 0

3 years ago