2 years ago

Find the sum: 1+10+19+28…, n=16

Mathematics

1 answer:

saveliy_v [14]2 years ago

7 0

Answer:

Step-by-step explanation:

1+10+19+28=58

sum=58+n

58+16=74

the answer is 74

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Ed has $5.06.<br> He finds $1.03.<br> About how much $ does he have now?

OverLord2011 [107]

Answer:

Ed now has $6.09

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3 years ago

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Use the point (-6,-8) to give the six trigonometric functions

vfiekz [6]

You can't exactly get the trigonometric functions using a point unless it's a vector,

so tanx = -8/-6 = 4/3 and from it we can get the other functions

sinx = -4/5
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3 years ago

What is the product of all constants $k$ such that the quadratic $x^2 + kx +15$ can be factored in the form $(x+a)(x+b)$, where

Setler79 [48]

Answer:

$k=-16,k=-8,k=8,k=16$

Step-by-step explanation:

We are given quadratic equations as

$x^2+kx+15$

and it can be factored as

$=(x+a)(x+b)$

now, we can multiply factor term

$(x+a)(x+b)=x^2+(a+b)x+ab$

now, we can compare

$x^2+(a+b)x+ab=x^2+kx+15$

so, we get

$k=a+b$

$ab=15$

we are given that

'a' and 'b' are integers

so, we can find all possible factors

$15=(-1\times -15),(1\times 15)$

$15=(-3\times -5),(3\times 5)$

so, we can find k

At $(-1\times -15)$ :

$k=a+b$

we can plug values

$k=-1-15$

$k=-16$

At $(1\times 15)$ :

$k=a+b$

we can plug values

$k=1+15$

$k=16$

At $(-3\times -5)$ :

$k=a+b$

we can plug values

$k=-3-5$

$k=-8$

At $(3\times 5)$ :

$k=a+b$

we can plug values

$k=3+5$

$k=8$

So, values of k are

$k=-16,k=-8,k=8,k=16$

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3 years ago

Thank you all for your help

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I didn't do anything but yay

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4 years ago

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3 years ago