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Anna35 [415]
3 years ago
10

Evaluate the iterated integral. $$ \int\limits_0^{2\pi}\int\limits_0^y\int\limits_0^x {\color{red}9} \cos(x+y+z)\,dz\,dx\,dy $$

Mathematics
1 answer:
KengaRu [80]3 years ago
4 0
\displaystyle\int_{y=0}^{y=2\pi}\int_{x=0}^{x=y}\int_{z=0}^{z=x}\cos(x+y+z)\,\mathrm dz\,\mathrm dx\,\mathrm dy=\int_{y=0}^{y=2\pi}\int_{x=0}^{x=y}\sin(x+y+z)\bigg|_{z=0}^{z=x}\,\mathrm dx\,\mathrm dy
\displaystyle=\int_{y=0}^{y=2\pi}\int_{x=0}^{x=y}\sin(2x+y)-\sin(x+y)\,\mathrm dx\,\mathrm dy
\displaystyle=\int_{y=0}^{y=2\pi}-\frac12\left(\cos(2x+y)-2\cos(x+y)\right)\bigg|_{x=0}^{x=y}\,\mathrm dx\,\mathrm dy
\displaystyle=\int_{y=0}^{y=2\pi}-\frac12\left((\cos3y-2\cos2y)-(\cos y-2\cos y)\right)\bigg|_{x=0}^{x=y}\,\mathrm dy
\displaystyle=-\frac12\int_{y=0}^{y=2\pi}(\cos3y-2\cos2y+\cos y)\,\mathrm dy
\displaystyle=-\frac12\left(\frac13\sin3y-\sin2y+\sin y\right)\bigg|_{y=0}^{y=2\pi}
=0
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Please help explanation if possible
posledela

Answer:

y =3x - 5

Step-by-step explanation:

Well one of the way to do this question is the formula given below your question, but for me, i rather do it this way

OK they gave u y=3x - 12

And they say another line is parallel, once u see the word parallel means they have the same angle, same slope, same gradient ( sorry if I give u the wrong terms, since I learn mine in Malay)

So first u got to understand the slope-intercept form

y = mx + c

y is your y coordinate

x is your x coordinate

m is your gradient ( as in how much the line slants)

c is the y - intercept, as in, if u draw a graph, the y-coordinate where your line touches the y-axis (the vertical line)

So since the say the both lines are parallel, so both of their "m" is the same that is 3. Why? Cuz just compare

y = mx + c

y = 3x - 12

Therefore the m is 3

Therefore u alredy got your first value, so put it in your slope intercept form

y = mx + c

y = 3x + c

Now how to find c? Very easy, just put in the value of y and x from the coordinate ( that the line youre finding is on) they gave u, just put the value in

They gave u

(1, - 2)

So when x = 1, y = - 2

Therefore put it in

y = 3x + c

-2 = 3 (1) + c

c = - 5

Since now u have your m and c value, your slope intercept form is done, just put it in

y = mx + c

y = 3x + (-5)

y = 3x -5

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